Certificate for #2612 ⟨a, b, c | aba=b, babc=1⟩

Completion settings:

[1] aba=b

Axiom: aba=b.

Referenced by [3], [4], [5].

[2] babc=1

Axiom: babc=1.

Referenced by [4], [7].

[3] bba=abb

Overlap of [1] aba=b with [1] aba=b:

ab a aba

Critical pair: abb=bba.

Flip LHS and RHS.

Referenced by [6].

[4] a=bbc

Overlap of [1] aba=b with [2] babc=1:

a ba babc

Critical pair: a=bbc.

Defines rule #4.

Referenced by [5], [6], [7].

[5] bbcbbbc=b

Overlap of [1] aba=b with [4] a=bbc:

aba a

Critical pair: bbcba=b.

Reduce LHS:

[4]bbcb(a)
⇒ bbcbbbc

Defines rule #3.

[6] bbbbc=bbcbb

Simplify [3] bba=abb.

Reduce LHS:

[4]bb(a)
⇒ bbbbc

Reduce RHS:

[4](a)bb
⇒ bbcbb

Defines rule #1.

[7] bbbcbc=1

Overlap of [2] babc=1 with [4] a=bbc:

b abc a

Critical pair: bbbcbc=1.

Defines rule #2.