Morphocompletion for #2609 ⟨a, b, c | aba=b, accb=1⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. accb ⇒ 1
2. accab ⇒ ccb
3. accaab ⇒ ccab
4. accaaab ⇒ ccaab
5. accaaaab ⇒ ccaaab
6. accaaaaab ⇒ ccaaaab
7. aba ⇒ b
8. ccba ⇒ 1
9. ccbb ⇒ ba
10. ccabb ⇒ baa
11. ccaabb ⇒ baaa
12. ccaaabb ⇒ baaaa
13. ccaaaabb ⇒ baaaaa
14. bccb ⇒ ab
15. bccab ⇒ aab
16. bccaab ⇒ aaab
17. bccaaab ⇒ aaaab
18. bccaaaab ⇒ aaaaab
19. bba ⇒ abb
...

Collecting factors up to length 4 / frequency 7:

[2/0]ab24lf:14,lp:1,ls:9,rf:10,rp:2,rs:9,re:1,lsrs:8
[2/1]cc23lf:17,lp:6,rf:5,rp:5,a:1
[2/2]aa22lf:22,rf:26,rp:4,rs:4,a:5
[2/3]ca13lf:13,rf:4,a:4
[2/4]bb12lf:6,lp:1,ls:5,rf:1,rs:1,lprs:10,a:2
[2/5]ac12lf:6,lp:6,a:1
[2/6]bc10lf:5,lp:5,a:3
[3/0]aab17lf:10,ls:7,rf:7,rp:1,rs:7,re:1,lsrs:6,a:5
[3/1]cca17lf:13,lp:4,rf:4,rp:4,a:4
[3/2]aaa12lf:12,rf:15,rp:3,rs:3,a:15
[3/3]acc12lf:6,lp:6,a:1
[3/4]bcc10lf:5,lp:5,a:3
[3/5]caa10lf:10,rf:3,a:14
[3/6]abb8lf:4,ls:4,rf:1,rp:1,rs:1,re:1,a:2

Considering [length 3 / frequency 0] aab=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aba=b, accb=1⟩.