Certificate for #2596 ⟨a, b, c | aba=b, aaca=1⟩

Completion settings:

[1] aba=b

Axiom: aba=b.

Referenced by [4], [5], [7], [8].

[2] aaca=1

Axiom: aaca=1.

Referenced by [3], [4], [5], [6], [9].

[3] aca=aac

Overlap of [2] aaca=1 with [2] aaca=1:

aac a aaca

Critical pair: aac=aca.

Flip LHS and RHS.

Referenced by [4], [6], [7], [9].

[4] ab=baac

Overlap of [1] aba=b with [2] aaca=1:

ab a aaca

Critical pair: ab=baca.

Reduce RHS:

[3]b(aca)
⇒ baac

Defines rule #3.

[5] aacb=ba

Overlap of [2] aaca=1 with [1] aba=b:

aac a aba

Critical pair: aacb=ba.

Referenced by [7].

[6] ca=ac

Overlap of [2] aaca=1 with [3] aca=aac:

aac a aca

Critical pair: aacaac=ca.

Reduce LHS:

[2](aaca)ac
⇒ ac

Flip LHS and RHS.

Defines rule #1.

Referenced by [8].

[7] acb=baa

Overlap of [3] aca=aac with [1] aba=b:

ac a aba

Critical pair: acb=aacba.

Reduce RHS:

[5](aacb)a
⇒ baa

Referenced by [8].

[8] cb=baaa

Overlap of [6] ca=ac with [1] aba=b:

c a aba

Critical pair: cb=acba.

Reduce RHS:

[7](acb)a
⇒ baaa

Defines rule #4.

[9] aaac=1

Overlap of [2] aaca=1 with [3] aca=aac:

a aca aca

Critical pair: aaac=1.

Defines rule #2.