Morphocompletion for #2199 ⟨a, b, c | aabc=1, acba=1⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cb ⇒ bc
2. baa ⇒ aab
3. bca ⇒ abc
4. caa ⇒ aac
5. aabc ⇒ 1
6. baac ⇒ 1
7. cabc ⇒ bcca
8. aabbc ⇒ b
9. bbcca ⇒ abbcc
10. cabbc ⇒ bccab
11. aababc ⇒ ba
12. aabbbc ⇒ bb
13. cababc ⇒ bccaba
14. aababbc ⇒ bab
15. aabbabc ⇒ bba
16. aabbbbc ⇒ bbb
...

Collecting factors up to length 4 / frequency 7:

[2/0]bc23lf:12,lp:1,ls:10,rf:6,rp:4,rs:2,re:1,lsrp:3,lprs:10
[2/1]aa19lf:10,lp:7,ls:2,rf:2,rp:2,lsrp:20
[2/2]ab14lf:14,rf:6,rp:2,rs:3
[2/3]ca12lf:6,lp:4,ls:2,rf:3,rs:1,lprs:1,a:7
[2/4]bb11lf:10,lp:1,rf:5,rp:3,rs:2,re:1,a:6
[2/5]ba8lf:6,lp:2,rf:4,rp:2,rs:3,re:1,a:12
[2/6]ac2lf:1,ls:1,rf:1,rs:1,a:16
[3/0]aab14lf:7,lp:7,rf:1,rp:1,rs:1,re:1
[3/1]bbc12lf:6,lp:1,ls:5,rf:1,a:6
[3/2]abc10lf:5,ls:5,rf:1,rp:1,rs:1,re:1
[3/3]cab6lf:3,lp:3,rf:2,rs:1,lprs:1,a:9
[3/4]abb6lf:6,rf:1,rp:1,a:6
[3/5]bab4lf:4,rf:1,rp:1,rs:1,re:1,a:12
[3/6]bbb3lf:3,rf:1,rp:1,rs:1,re:1,a:11

Considering [length 2 / frequency 0] bc=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aabc=1, acba=1⟩.