Morphocompletion for #1851 ⟨a, b, c | aba=bb, acb=1⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. bbba ⇒ abbb
2. cbbb ⇒ ba
3. bbcb ⇒ ab
4. aba ⇒ bb
5. acb ⇒ 1
6. cabbb ⇒ baa
7. cba ⇒ 1
8. cbbab ⇒ babcb
9. bbcab ⇒ aab
10. acab ⇒ bcb
11. caabbb ⇒ baaa
12. cabbab ⇒ baabcb
13. cbbaab ⇒ babcab
14. bbcaab ⇒ aaab
15. acaab ⇒ bcab
16. caaabbb ⇒ baaaa
17. bbcaaab ⇒ aaaab
18. acaaab ⇒ bcaab
19. acaaaab ⇒ bcaaab
...

Collecting factors up to length 4 / frequency 7:

[2/0]ab26lf:15,lp:1,ls:10,rf:12,rp:2,rs:8,re:1,lsrs:7
[2/1]bb26lf:17,lp:5,ls:4,rf:3,rp:1,rs:2,re:1,lprs:1
[2/2]ca15lf:11,lp:4,rf:4,a:4
[2/3]aa13lf:13,rf:16,rp:3,rs:3,a:5
[2/4]cb12lf:6,lp:4,ls:2,rf:3,rs:3,lprs:1,a:1
[2/5]ac10lf:5,lp:5,a:1
[2/6]ba9lf:6,ls:3,rf:7,rp:7,rs:1,re:1
[3/0]aab14lf:8,ls:6,rf:6,rp:1,rs:5,re:1,lsrs:4,a:5
[3/1]bbb10lf:5,lp:1,ls:4,rf:1,rs:1,lprs:10,a:2
[3/2]caa9lf:7,lp:2,rf:2,a:7
[3/3]aca8lf:4,lp:4,a:4
[3/4]cab8lf:4,lp:2,ls:2,rf:2,rs:2,a:4
[3/5]bbc8lf:4,lp:4,a:3
[3/6]cbb6lf:3,lp:3,a:10

Considering [length 2 / frequency 0] ab=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aba=bb, acb=1⟩.