Certificate for #1850 ⟨a, b, c | aba=bb, aca=1⟩

Completion settings:

[1] aba=bb

Axiom: aba=bb.

Referenced by [4], [5].

[2] aca=1

Axiom: aca=1.

Referenced by [3], [4], [5], [7], [9].

[3] ca=ac

Overlap of [2] aca=1 with [2] aca=1:

ac a aca

Critical pair: ac=ca.

Flip LHS and RHS.

Defines rule #4.

Referenced by [4], [9].

[4] bbac=ab

Overlap of [1] aba=bb with [2] aca=1:

ab a aca

Critical pair: ab=bbca.

Reduce RHS:

[3]bb(ca)
⇒ bbac

Flip LHS and RHS.

Referenced by [6].

[5] ba=acbb

Overlap of [2] aca=1 with [1] aba=bb:

ac a aba

Critical pair: acbb=ba.

Flip LHS and RHS.

Defines rule #3.

Referenced by [6].

[6] acbbcbbc=ab

Simplify [4] bbac=ab.

Reduce LHS:

[5]b(ba)c
[5]⇒ (ba)cbbc
⇒ acbbcbbc

Referenced by [7].

[7] cbbcbbc=b

Overlap of [2] aca=1 with [6] acbbcbbc=ab:

ac a acbbcbbc

Critical pair: acab=cbbcbbc.

Reduce LHS:

[2](aca)b
⇒ b

Flip LHS and RHS.

Defines rule #2.

Referenced by [8], [10].

[8] cbbb=bbbc

Overlap of [7] cbbcbbc=b with [7] cbbcbbc=b:

cbb cbbc cbbcbbc

Critical pair: cbbb=bbbc.

Defines rule #1.

[9] aac=1

Overlap of [2] aca=1 with [3] ca=ac:

a ca ca

Critical pair: aac=1.

Defines rule #6.

Referenced by [10].

[10] aab=bbcbbc

Overlap of [9] aac=1 with [7] cbbcbbc=b:

aa c cbbcbbc

Critical pair: aab=bbcbbc.

Defines rule #5.