Morphocompletion for #1848 ⟨a, b, c | aba=ba, caa=1⟩

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aba ⇒ ba
2. caa ⇒ 1
3. cba ⇒ ba
4. abba ⇒ bba
5. cbba ⇒ bba
6. abbba ⇒ bbba
7. cbbba ⇒ bbba
8. abbbba ⇒ bbbba
9. cbbbba ⇒ bbbba
10. abbbbba ⇒ bbbbba
11. cbbbbba ⇒ bbbbba
12. abbbbbba ⇒ bbbbbba
13. cbbbbbba ⇒ bbbbbba
14. abbbbbbba ⇒ bbbbbbba
15. cbbbbbbba ⇒ bbbbbbba
16. abbbbbbbba ⇒ bbbbbbbba
17. cbbbbbbbba ⇒ bbbbbbbba
18. abbbbbbbbba ⇒ bbbbbbbbba
19. cbbbbbbbbba ⇒ bbbbbbbbba
20. abbbbbbbbbba ⇒ bbbbbbbbbba
...

Collecting factors up to length 4 / frequency 7:

[2/0]bb81lf:81,rf:81,rp:17,a:2
[2/1]ba38lf:19,ls:19,rf:19,rp:2,rs:19,re:2,lsrp:2,lsrs:19
[2/2]ab20lf:10,lp:10
[2/3]cb18lf:9,lp:9,a:3
[2/4]ca2lf:1,lp:1,a:1
[2/5]aa2lf:1,ls:1,a:1
[3/0]bbb64lf:64,rf:64,rp:15,a:5
[3/1]bba34lf:17,ls:17,rf:17,rp:2,rs:17,re:2,lsrp:2,lsrs:17,a:2
[3/2]abb18lf:9,lp:9,a:2
[3/3]cbb16lf:8,lp:8,a:4

Considering [length 2 / frequency 1] ba=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aba=ba, caa=1⟩.