Morphocompletion for #1811 ⟨a, b, c | aba=ab, bac=1⟩

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abc ⇒ a
2. abbc ⇒ ab
3. abbbc ⇒ abb
4. abbbbc ⇒ abbb
5. abbbbbc ⇒ abbbb
6. abbbbbbc ⇒ abbbbb
7. abbbbbbbc ⇒ abbbbbb
8. abbbbbbbbc ⇒ abbbbbbb
9. abbbbbbbbbc ⇒ abbbbbbbb
10. abbbbbbbbbbc ⇒ abbbbbbbbb
11. bac ⇒ 1
12. aba ⇒ ab
13. abba ⇒ abb
14. abbba ⇒ abbb
15. abbbba ⇒ abbbb
16. abbbbba ⇒ abbbbb
17. abbbbbba ⇒ abbbbbb
18. abbbbbbba ⇒ abbbbbbb
19. abbbbbbbba ⇒ abbbbbbbb
20. abbbbbbbbba ⇒ abbbbbbbbb
...

Collecting factors up to length 4 / frequency 7:

[2/0]bb81lf:81,rf:72,rs:16,a:2
[2/1]ab38lf:19,lp:19,rf:18,rp:18,rs:2,re:2,lprp:18,lprs:2
[2/2]ba20lf:10,lp:1,ls:9
[2/3]bc20lf:10,ls:10,a:3
[2/4]ac2lf:1,ls:1,a:1
[3/0]bbb64lf:64,rf:56,rs:14,a:5
[3/1]abb34lf:17,lp:17,rf:16,rp:16,rs:2,re:2,lprp:16,lprs:2,a:2
[3/2]bbc18lf:9,ls:9,a:4
[3/3]bba16lf:8,ls:8,a:2

Considering [length 2 / frequency 1] ab=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aba=ab, bac=1⟩.