Morphocompletion for #1723 ⟨a, b, c | aab=ca, abc=1⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abc ⇒ 1
2. acbc ⇒ ab
3. accbc ⇒ acb
4. acccbc ⇒ accb
5. accccbc ⇒ acccb
6. acccccbc ⇒ accccb
7. cab ⇒ 1
8. cac ⇒ a
9. aab ⇒ ca
10. aacb ⇒ cca
11. aaccb ⇒ ccca
12. aacccb ⇒ cccca
13. aaccccb ⇒ ccccca
14. aba ⇒ ac
15. acba ⇒ acc
16. accba ⇒ accc
17. acccba ⇒ acccc
18. accccba ⇒ accccc
19. caa ⇒ aac
...

Collecting factors up to length 4 / frequency 7:

[2/0]ac24lf:14,lp:9,ls:1,rf:10,rp:9,rs:2,re:1,lprp:8,a:2
[2/1]cc22lf:22,rf:26,rp:4,rs:4,a:7
[2/2]cb17lf:13,ls:4,rf:4,rs:4,a:6
[2/3]aa12lf:6,lp:5,ls:1,rf:1,rp:1,lsrp:10
[2/4]bc12lf:6,ls:6,a:1
[2/5]ba10lf:5,ls:5,a:3
[2/6]ab8lf:4,lp:2,ls:2,rf:1,rp:1,rs:1,re:1
[3/0]acc17lf:10,lp:7,rf:7,rp:7,rs:1,re:1,lprp:6,a:7
[3/1]ccb13lf:10,ls:3,rf:3,rs:3,a:10
[3/2]ccc12lf:12,rf:15,rp:3,rs:3,a:12
[3/3]cbc10lf:5,ls:5,a:6
[3/4]aac8lf:4,lp:4,rf:1,rp:1,rs:1,re:1,a:4
[3/5]cba8lf:4,ls:4,a:7
[3/6]acb6lf:3,lp:2,ls:1,rf:1,rp:1,rs:1,re:1,a:6

Considering [length 2 / frequency 0] ac=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aab=ca, abc=1⟩.