Certificate for #1723 ⟨a, b, c | aab=ca, abc=1⟩

Completion settings:

[1] aab=ca

Axiom: aab=ca.

Referenced by [4], [14].

[2] abc=1

Axiom: abc=1.

Referenced by [4], [5], [7], [9].

[3] ac=d

Axiom: ac=d.

Referenced by [4], [6], [8], [10].

[4] a=cd

Overlap of [1] aab=ca with [2] abc=1:

a ab abc

Critical pair: a=cac.

Reduce RHS:

[3]c(ac)
⇒ cd

Defines rule #11.

Referenced by [5], [6], [7], [8], [9], [10], [14], [15].

[5] cdbc=1

Overlap of [2] abc=1 with [4] a=cd:

abc a

Critical pair: cdbc=1.

Referenced by [9], [10], [11], [16].

[6] cdc=d

Overlap of [3] ac=d with [4] a=cd:

ac a

Critical pair: cdc=d.

Defines rule #1.

Referenced by [7], [8], [12], [15].

[7] cdbd=dc

Overlap of [2] abc=1 with [6] cdc=d:

ab c cdc

Critical pair: abd=dc.

Reduce LHS:

[4](a)bd
⇒ cdbd

Defines rule #7.

Referenced by [11], [12], [13].

[8] ddc=cdd

Overlap of [3] ac=d with [6] cdc=d:

a c cdc

Critical pair: ad=ddc.

Reduce LHS:

[4](a)d
⇒ cdd

Flip LHS and RHS.

Defines rule #5.

[9] dbc=cdb

Overlap of [2] abc=1 with [5] cdbc=1:

ab c cdbc

Critical pair: ab=dbc.

Reduce LHS:

[4](a)b
⇒ cdb

Flip LHS and RHS.

Defines rule #2.

Referenced by [10], [11], [12], [16].

[10] dcdb=cd

Overlap of [3] ac=d with [5] cdbc=1:

a c cdbc

Critical pair: a=ddbc.

Reduce LHS:

[4](a)
⇒ cd

Reduce RHS:

[9]d(dbc)
⇒ dcdb

Flip LHS and RHS.

Defines rule #10.

[11] dcbc=db

Overlap of [9] dbc=cdb with [5] cdbc=1:

db c cdbc

Critical pair: db=cdbdbc.

Reduce RHS:

[7](cdbd)bc
⇒ dcbc

Flip LHS and RHS.

Defines rule #8.

[12] dcc=dbd

Overlap of [9] dbc=cdb with [6] cdc=d:

db c cdc

Critical pair: dbd=cdbdc.

Reduce RHS:

[7](cdbd)c
⇒ dcc

Flip LHS and RHS.

Defines rule #3.

Referenced by [13].

[13] dcbd=dbdc

Overlap of [7] cdbd=dc with [12] dcc=dbd:

cdb d dcc

Critical pair: cdbdbd=dccc.

Reduce LHS:

[7](cdbd)bd
⇒ dcbd

Reduce RHS:

[12](dcc)c
⇒ dbdc

Defines rule #9.

[14] aab=ccd

Simplify [1] aab=ca.

Reduce RHS:

[4]c(a)
⇒ ccd

Referenced by [15].

[15] ddb=ccd

Overlap of [14] aab=ccd with [4] a=cd:

aab a

Critical pair: cdab=ccd.

Reduce LHS:

[4]cd(a)b
[6]⇒ (cdc)db
⇒ ddb

Defines rule #4.

[16] ccdb=1

Overlap of [5] cdbc=1 with [9] dbc=cdb:

c dbc dbc

Critical pair: ccdb=1.

Defines rule #6.