Morphocompletion for #1662 ⟨a, b, c | aab=ba, bac=1⟩

Solved by morph:2/3,2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: lhsLimit

#Rule
1. ba ⇒ aab
2. aabc ⇒ 1
3. aaaabbc ⇒ b
4. aaaaaaaabbbc ⇒ bb
5. aaaaaaaaaaaaaaaabbbbc ⇒ bbb
6. aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaabbbbbc ⇒ bbbb
...

Collecting factors up to length 4 / frequency 4:

[2/0]aa62lf:57,lp:5,rf:1,rp:1
[2/1]bb10lf:10,rf:6,rp:3,rs:3,re:1,a:2
[2/2]bc10lf:5,ls:5,a:1
[2/3]ab5lf:5,rf:1,rs:1
[3/0]aaa56lf:52,lp:4,a:2
[3/1]bbc8lf:4,ls:4,a:2
[3/2]bbb6lf:6,rf:3,rp:2,rs:2,re:1,a:3
[3/3]aab6lf:5,lp:1,rf:1,rp:1,rs:1,re:1

Considering [length 2 / frequency 3] ab=d.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: workMaxLimit

#Rule
1. da ⇒ aad
2. adc ⇒ 1
3. ab ⇒ d
4. ba ⇒ ad
5. addc ⇒ b
6. adb ⇒ bd
7. adddc ⇒ bb
8. addb ⇒ bbd
9. addddc ⇒ bbb
10. adddb ⇒ bbbd
11. adddddc ⇒ bbbb
12. addddb ⇒ bbbbd
13. addddddc ⇒ bbbbb
14. adddddb ⇒ bbbbbd
15. adddddddc ⇒ bbbbbb
16. addddddb ⇒ bbbbbbd
17. addddddddc ⇒ bbbbbbb
18. adddddddb ⇒ bbbbbbbd
...

Collecting factors up to length 6 / frequency 3:

[2/0]dd49lf:49,a:5
[2/1]ad30lf:15,lp:15,rf:2,rp:1,rs:2,re:1
[2/2]dc16lf:8,ls:8,a:3
[3/0]ddd36lf:36,a:7
[3/1]add26lf:13,lp:13,a:5
[3/2]ddc14lf:7,ls:7,a:5
[4/0]dddd25lf:25,a:9
[4/1]addd22lf:11,lp:11,a:7
[4/2]dddc12lf:6,ls:6,a:7
[5/0]adddd18lf:9,lp:9,a:9
[5/1]ddddd16lf:16,a:11
[5/2]ddddc10lf:5,ls:5,a:9

Considering [length 2 / frequency 1] ad=e.

Step 3

Rewriting system is complete. See ⟨a, b, c | aab=ba, bac=1⟩.