Morphocompletion for #1658 ⟨a, b, c | aab=ba, abc=1⟩

Solved by morph:2/2,5/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: lhsLimit

#Rule
1. ba ⇒ aab
2. abc ⇒ 1
3. aabbc ⇒ b
4. aaaabbbc ⇒ bb
5. aaaaaaaabbbbc ⇒ bbb
6. aaaaaaaaaaaaaaaabbbbbc ⇒ bbbb
7. aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaabbbbbbc ⇒ bbbbb
...

Collecting factors up to length 4 / frequency 4:

[2/0]aa62lf:57,lp:5,rf:1,rp:1
[2/1]bb15lf:15,rf:10,rp:4,rs:4,re:1,a:2
[2/2]bc12lf:6,ls:6,a:1
[2/3]ab7lf:6,lp:1,rf:1,rs:1
[3/0]aaa56lf:52,lp:4,a:3
[3/1]bbb10lf:10,rf:6,rp:3,rs:3,re:1,a:3
[3/2]bbc10lf:5,ls:5,a:2
[3/3]aab6lf:5,lp:1,rf:1,rp:1,rs:1,re:1

Considering [length 2 / frequency 2] bc=d.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: lhsLimit

#Rule
1. ad ⇒ 1
2. ba ⇒ aab
3. bc ⇒ d
4. aabd ⇒ b
5. aaaabbd ⇒ bb
6. aaaaaaaabbbd ⇒ bbb
7. aaaaaaaaaaaaaaaabbbbd ⇒ bbbb
8. aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaabbbbbd ⇒ bbbbb
...

Collecting factors up to length 6 / frequency 3:

[2/0]aa62lf:57,lp:5,rf:1,rp:1
[2/1]bb10lf:10,rf:10,rp:4,rs:4,re:1,a:5
[2/2]bd10lf:5,ls:5,a:4
[3/0]aaa56lf:52,lp:4,a:5
[3/1]bbd8lf:4,ls:4,a:5
[3/2]bbb6lf:6,rf:6,rp:3,rs:3,re:1,a:6
[4/0]aaaa52lf:48,lp:4,a:5
[4/1]bbbd6lf:3,ls:3,a:6
[4/2]aabb4lf:4,a:5
[5/0]aaaaa47lf:44,lp:3,a:6
[5/1]aaaab5lf:4,lp:1,a:5
[5/2]bbbbd4lf:2,ls:2,a:7

Considering [length 5 / frequency 1] aaaab=e.

Step 3

Rewriting system is complete. See ⟨a, b, c | aab=ba, abc=1⟩.