| Back: | ⟨a, b, c | aab=ab, cba=1⟩ |
|---|
Completion settings:
Axiom: aab=ab.
Referenced by [3].
Axiom: cba=1.
Defines rule #2.
Overlap of [2] cba=1 with [1] aab=ab:
Critical pair: cbab=ab.
Reduce LHS:
| [2] | (cba)b |
| ⇒ b |
Flip LHS and RHS.
Defines rule #1.
Referenced by [4].
Overlap of [2] cba=1 with [3] ab=b:
Critical pair: cbb=b.
Defines rule #3.