Certificate for #1626 ⟨a, b, c | aab=ab, cba=1⟩

Completion settings:

[1] aab=ab

Axiom: aab=ab.

Referenced by [3].

[2] cba=1

Axiom: cba=1.

Defines rule #2.

Referenced by [3], [4].

[3] ab=b

Overlap of [2] cba=1 with [1] aab=ab:

cb a aab

Critical pair: cbab=ab.

Reduce LHS:

[2](cba)b
⇒ b

Flip LHS and RHS.

Defines rule #1.

Referenced by [4].

[4] cbb=b

Overlap of [2] cba=1 with [3] ab=b:

cb a ab

Critical pair: cbb=b.

Defines rule #3.