Morphocompletion for #1585 ⟨a, b, c | aaa=bc, acb=1⟩

Solved by morph:2/4. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaba ⇒ b
2. aaabb ⇒ baaba
3. cba ⇒ 1
4. cbb ⇒ aaba
5. acaaa ⇒ c
6. acb ⇒ 1
7. acab ⇒ caba
8. acaab ⇒ caaba
9. bc ⇒ aaa
10. bac ⇒ 1
11. baac ⇒ caaaaaab
12. baaca ⇒ caaab
13. aabaac ⇒ cb
14. ccb ⇒ acaa
15. ccaaab ⇒ aca
16. ccaaaaaab ⇒ ac
17. acaac ⇒ ccaaa
...

Collecting factors up to length 4 / frequency 7:

[2/0]aa23lf:19,lp:3,ls:1,rf:15,rp:2,rs:3
[2/1]ac19lf:10,lp:5,ls:4,rf:3,rp:3,rs:1,re:1,a:1
[2/2]ab11lf:7,ls:4,rf:6,rs:2,a:9
[2/3]ba11lf:6,lp:3,ls:2,rf:5,rp:1,rs:4,a:7
[2/4]cb8lf:4,lp:2,ls:2,rf:1,rp:1,rs:1,re:1,a:1
[2/5]ca8lf:7,ls:1,rf:7,rp:4,rs:1,lsrp:1,a:2
[2/6]cc6lf:3,lp:3,rf:1,rp:1,a:3
[3/0]aaa11lf:8,lp:2,ls:1,rf:7,rp:1,rs:2,re:1
[3/1]aca10lf:5,lp:4,ls:1,rf:2,rp:2,rs:1,re:1,a:2
[3/2]aab10lf:6,lp:1,ls:3,rf:5,rp:1,rs:2,a:9
[3/3]aac7lf:4,ls:3,a:4
[3/4]caa5lf:5,rf:5,rp:3,rs:1,a:2
[3/5]baa5lf:3,lp:2,rf:1,rp:1,a:9
[3/6]cca4lf:2,lp:2,rf:1,rp:1,a:4

Considering [length 2 / frequency 4] cb=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aaa=bc, acb=1⟩.