Certificate for #1532 ⟨a, b, c | ab=1, cac=ac⟩

Completion settings:

[1] ab=1

Axiom: ab=1.

Defines rule #2.

Referenced by [5].

[2] cac=ac

Axiom: cac=ac.

Referenced by [4].

[3] ca=d

Axiom: ca=d.

Referenced by [4], [5], [6], [9].

[4] ac=dc

Overlap of [2] cac=ac with [3] ca=d:

cac ca

Critical pair: dc=ac.

Flip LHS and RHS.

Referenced by [7].

[5] c=db

Overlap of [3] ca=d with [1] ab=1:

c a ab

Critical pair: c=db.

Defines rule #5.

Referenced by [6], [7], [9].

[6] dba=d

Overlap of [3] ca=d with [5] c=db:

ca c

Critical pair: dba=d.

Defines rule #4.

Referenced by [8].

[7] adb=ddb

Simplify [4] ac=dc.

Reduce LHS:

[5]a(c)
⇒ adb

Reduce RHS:

[5]d(c)
⇒ ddb

Referenced by [8].

[8] ad=dd

Overlap of [7] adb=ddb with [6] dba=d:

a db dba

Critical pair: ad=ddba.

Reduce RHS:

[6]d(dba)
⇒ dd

Defines rule #3.

Referenced by [9].

[9] dbdd=dd

Overlap of [3] ca=d with [8] ad=dd:

c a ad

Critical pair: cdd=dd.

Reduce LHS:

[5](c)dd
⇒ dbdd

Defines rule #1.