Certificate for #1355 ⟨a, b, c | ab=1, bbca=c⟩

Completion settings:

[1] ab=1

Axiom: ab=1.

Defines rule #4.

Referenced by [5], [6], [7], [8], [10].

[2] bbca=c

Axiom: bbca=c.

Referenced by [5], [6], [13].

[3] ac=d

Axiom: ac=d.

Defines rule #7.

Referenced by [5], [9], [11].

[4] ad=e

Axiom: ad=e.

Defines rule #9.

Referenced by [7], [12].

[5] bca=d

Overlap of [1] ab=1 with [2] bbca=c:

a b bbca

Critical pair: ac=bca.

Reduce LHS:

[3](ac)
⇒ d

Flip LHS and RHS.

Referenced by [7], [8], [13], [14].

[6] cb=bbc

Overlap of [2] bbca=c with [1] ab=1:

bbc a ab

Critical pair: bbc=cb.

Flip LHS and RHS.

Defines rule #1.

[7] ca=e

Overlap of [1] ab=1 with [5] bca=d:

a b bca

Critical pair: ad=ca.

Reduce LHS:

[4](ad)
⇒ e

Flip LHS and RHS.

Defines rule #10.

Referenced by [9], [10], [11], [12], [14].

[8] db=bc

Overlap of [5] bca=d with [1] ab=1:

bc a ab

Critical pair: bc=db.

Flip LHS and RHS.

Defines rule #3.

[9] ae=da

Overlap of [3] ac=d with [7] ca=e:

a c ca

Critical pair: ae=da.

Defines rule #12.

[10] eb=c

Overlap of [7] ca=e with [1] ab=1:

c a ab

Critical pair: c=eb.

Flip LHS and RHS.

Defines rule #6.

[11] cd=ec

Overlap of [7] ca=e with [3] ac=d:

c a ac

Critical pair: cd=ec.

Defines rule #8.

[12] ce=ed

Overlap of [7] ca=e with [4] ad=e:

c a ad

Critical pair: ce=ed.

Defines rule #11.

[13] bd=c

Overlap of [2] bbca=c with [5] bca=d:

b bca bca

Critical pair: bd=c.

Defines rule #2.

[14] be=d

Overlap of [5] bca=d with [7] ca=e:

b ca ca

Critical pair: be=d.

Defines rule #5.