Certificate for #1305 ⟨a, b, c | ab=1, abca=c⟩

Completion settings:

[1] ab=1

Axiom: ab=1.

Defines rule #1.

Referenced by [2], [3].

[2] ca=c

Axiom: abca=c.

Reduce LHS:

[1](ab)ca
⇒ ca

Defines rule #2.

Referenced by [3].

[3] cb=c

Overlap of [2] ca=c with [1] ab=1:

c a ab

Critical pair: c=cb.

Flip LHS and RHS.

Defines rule #3.