Certificate for #1302 ⟨a, b, c | ab=1, abbc=c⟩

Completion settings:

[1] ab=1

Axiom: ab=1.

Defines rule #1.

Referenced by [2], [3].

[2] bc=c

Axiom: abbc=c.

Reduce LHS:

[1](ab)bc
⇒ bc

Defines rule #3.

Referenced by [3].

[3] ac=c

Overlap of [1] ab=1 with [2] bc=c:

a b bc

Critical pair: ac=c.

Defines rule #2.