Certificate for #1282 ⟨a, b, c | ab=1, aabc=a⟩

Completion settings:

[1] ab=1

Axiom: ab=1.

Defines rule #1.

Referenced by [2].

[2] ac=a

Axiom: aabc=a.

Reduce LHS:

[1]a(ab)c
⇒ ac

Defines rule #2.