#114 ⟨a, b, c | ab=a, cbb=1⟩

Properties

Sum of relation sides is 6
Infinite non-cancellative non-commutative monoid
Element a has infinite order
Not left cancellative, because left multiplication by a is not injective:
- a ⋅ b = a and a ⋅ 1 = a, however b ≠ 1
Not right cancellative, because right multiplication by b² is not injective:
- b²c ⋅ b² = b² and 1 ⋅ b² = b², however b²c ≠ 1

Format:	Pretty Plain
Word:
	Enter a word above to compute its normal form. Tips: Lowercase letters stand for generators. Spaces are ignored. Numbers repeat the previous letter, e.g. `b90`.
Strategy:	Leftmost Rightmost
Result:	1 1

#	Rule	Proof
1.	ab ⇒ a	[1]
2.	cb² ⇒ 1	[2]

# abc:ab=a,cbb=1 abc - -
ab=a
cbb=1

The mapping is from the listed presentation's alphabet to the current rewriting system's alphabet.

1 total

Σ	#	Presentation	Mapping
8	1816	⟨a, b, c \| aba=ab, caa=1⟩	φ(a) = b, φ(b) = a, φ(c) = c