Morphocompletion for #1114 ⟨a, b, c | aa=1, bcccb=1⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aa ⇒ 1
2. cbb ⇒ bbc
3. cccb ⇒ bccc
4. bbccc ⇒ 1
5. bbcbccc ⇒ cb
6. bbccbccc ⇒ ccb
7. bbcbcbccc ⇒ cbcb
8. bbcbccbccc ⇒ cbccb
9. bbccbcbccc ⇒ ccbcb
10. bbcbcbcbccc ⇒ cbcbcb
11. bbccbccbccc ⇒ ccbccb
12. bbcbcbccbccc ⇒ cbcbccb
...

Collecting factors up to length 4 / frequency 7:

[2/0]cc36lf:26,lp:1,ls:9,rf:8,rp:3,rs:1,lsrp:3,lprs:1,a:2
[2/1]bc25lf:25,rf:10,rp:1,rs:1,a:2
[2/2]cb20lf:18,lp:1,ls:1,rf:16,rp:5,rs:8,re:1,a:2
[2/3]bb20lf:10,lp:9,ls:1,rf:1,rp:1,lsrp:10,a:3
[3/0]ccc20lf:10,lp:1,ls:9,rf:1,rs:1,lprs:10,a:2
[3/1]bbc18lf:9,lp:9,rf:1,rp:1,rs:1,re:1,a:3
[3/2]cbc16lf:16,rf:8,rp:4,a:4
[3/3]bcc15lf:15,rf:4,rp:1,a:2
[3/4]bcb10lf:10,rf:5,rs:3,a:4
[3/5]ccb8lf:7,ls:1,rf:6,rp:3,rs:4,re:1,a:2

Considering [length 3 / frequency 0] ccc=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | aa=1, bcccb=1⟩.