Morphocompletion for #1036 ⟨a, b, c | ab=c, bac=c⟩

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. bac ⇒ c
3. cac ⇒ ac
4. baac ⇒ ac
5. caac ⇒ aac
6. baaac ⇒ aac
7. caaac ⇒ aaac
8. baaaac ⇒ aaac
9. caaaac ⇒ aaaac
10. baaaaac ⇒ aaaac
11. caaaaac ⇒ aaaaac
12. baaaaaac ⇒ aaaaac
13. caaaaaac ⇒ aaaaaac
14. baaaaaaac ⇒ aaaaaac
15. caaaaaaac ⇒ aaaaaaac
16. baaaaaaaac ⇒ aaaaaaac
17. caaaaaaaac ⇒ aaaaaaaac
18. baaaaaaaaac ⇒ aaaaaaaac
19. caaaaaaaaac ⇒ aaaaaaaaac
20. baaaaaaaaaac ⇒ aaaaaaaaac
...

Collecting factors up to length 4 / frequency 7:

[2/0]aa81lf:81,rf:72,rp:16,a:3
[2/1]ac38lf:19,ls:19,rf:18,rp:2,rs:18,re:2,lsrp:2,lsrs:18,a:1
[2/2]ba20lf:10,lp:10,a:1
[2/3]ca18lf:9,lp:9,a:2
[3/0]aaa64lf:64,rf:56,rp:14,a:5
[3/1]aac34lf:17,ls:17,rf:16,rp:2,rs:16,re:2,lsrp:2,lsrs:16,a:3
[3/2]baa18lf:9,lp:9,a:3
[3/3]caa16lf:8,lp:8,a:4

Considering [length 2 / frequency 1] ac=d.

Step 2

Rewriting system is complete. See ⟨a, b, c | ab=c, bac=c⟩.