| Back: | ⟨a, b | aa=a, babbab=a⟩ |
|---|
Completion settings:
Axiom: aa=a.
Defines rule #1.
Referenced by [4], [5], [6], [9].
Axiom: babbab=a.
Overlap of [2] babbab=a with [2] babbab=a:
Critical pair: baba=abab.
Overlap of [2] babbab=a with [2] babbab=a:
Critical pair: babbaa=aabbab.
Reduce LHS:
| [1] | babb(aa) |
| ⇒ babba |
Reduce RHS:
| [1] | (aa)bbab |
| ⇒ abbab |
Overlap of [2] babbab=a with [3] baba=abab:
Critical pair: bababab=aa.
Reduce LHS:
| [3] | (baba)bab |
| [4] | ⇒ a(babba)b |
| [1] | ⇒ (aa)bbabb |
| ⇒ abbabb |
Reduce RHS:
| [1] | (aa) |
| ⇒ a |
Referenced by [7].
Overlap of [3] baba=abab with [3] baba=abab:
Critical pair: baabab=ababba.
Reduce LHS:
| [1] | b(aa)bab |
| [3] | ⇒ (baba)b |
| ⇒ ababb |
Reduce RHS:
| [4] | a(babba) |
| [1] | ⇒ (aa)bbab |
| ⇒ abbab |
Flip LHS and RHS.
Referenced by [7].
Simplify [5] abbabb=a.
Reduce LHS:
| [6] | (abbab)b |
| ⇒ ababbb |
Overlap of [3] baba=abab with [7] ababbb=a:
Critical pair: ba=ababbbb.
Reduce RHS:
| [7] | (ababbb)b |
| ⇒ ab |
Defines rule #2.
Referenced by [9].
Overlap of [7] ababbb=a with [8] ba=ab:
Critical pair: aabbbb=a.
Reduce LHS:
| [1] | (aa)bbbb |
| ⇒ abbbb |
Defines rule #3.