Certificate for #6501 ⟨a, b | aba=b, aabbb=b⟩

Completion settings:

[1] aba=b

Axiom: aba=b.

Referenced by [3], [5], [8].

[2] aabbb=b

Axiom: aabbb=b.

Referenced by [4].

[3] abb=bba

Overlap of [1] aba=b with [1] aba=b:

ab a aba

Critical pair: abb=bba.

Referenced by [4], [6], [7], [9], [10], [11].

[4] bbaab=b

Simplify [2] aabbb=b.

Reduce LHS:

[3]a(abb)b
[3]⇒ (abb)ab
⇒ bbaab

Referenced by [5], [6], [10].

[5] bbab=ba

Overlap of [4] bbaab=b with [1] aba=b:

bba ab aba

Critical pair: bbab=ba.

Referenced by [7], [8], [9], [10].

[6] bbaaab=ab

Overlap of [3] abb=bba with [4] bbaab=b:

a bb bbaab

Critical pair: ab=bbaaab.

Flip LHS and RHS.

Referenced by [11].

[7] baab=bbaa

Overlap of [3] abb=bba with [5] bbab=ba:

ab b bbab

Critical pair: abba=bbabab.

Reduce LHS:

[3](abb)a
⇒ bbaa

Reduce RHS:

[5](bbab)ab
⇒ baab

Flip LHS and RHS.

Referenced by [9].

[8] bbb=baa

Overlap of [5] bbab=ba with [1] aba=b:

bb ab aba

Critical pair: bbb=baa.

Defines rule #3.

Referenced by [9], [11].

[9] bab=bbaaa

Overlap of [5] bbab=ba with [3] abb=bba:

bb ab abb

Critical pair: bbbba=bab.

Reduce LHS:

[8](bbb)ba
[7]⇒ (baab)a
⇒ bbaaa

Flip LHS and RHS.

Referenced by [10], [11].

[10] baaaa=b

Overlap of [3] abb=bba with [9] bab=bbaaa:

ab b bab

Critical pair: abbbaaa=bbaab.

Reduce LHS:

[3](abb)baaa
[5]⇒ (bbab)aaa
⇒ baaaa

Reduce RHS:

[4](bbaab)
⇒ b

Defines rule #1.

[11] ab=baaa

Overlap of [9] bab=bbaaa with [3] abb=bba:

b ab abb

Critical pair: bbba=bbaaab.

Reduce LHS:

[8](bbb)a
⇒ baaa

Reduce RHS:

[6](bbaaab)
⇒ ab

Flip LHS and RHS.

Defines rule #2.