Certificate for #5399 ⟨a, b | aab=ba, bab=ab⟩

Completion settings:

[1] aab=ba

Axiom: aab=ba.

Referenced by [3], [4], [5], [6], [7], [8].

[2] bab=ab

Axiom: bab=ab.

Referenced by [3], [4], [6], [7].

[3] bba=aba

Overlap of [1] aab=ba with [2] bab=ab:

aa b bab

Critical pair: aaab=baab.

Reduce LHS:

[1]a(aab)
⇒ aba

Reduce RHS:

[1]b(aab)
⇒ bba

Flip LHS and RHS.

Referenced by [4], [6].

[4] aba=ba

Overlap of [2] bab=ab with [2] bab=ab:

ba b bab

Critical pair: baab=abab.

Reduce LHS:

[1]b(aab)
[3]⇒ (bba)
⇒ aba

Reduce RHS:

[2]a(bab)
[1]⇒ (aab)
⇒ ba

Referenced by [5], [6], [7].

[5] baa=ba

Overlap of [1] aab=ba with [4] aba=ba:

a ab aba

Critical pair: aba=baa.

Reduce LHS:

[4](aba)
⇒ ba

Flip LHS and RHS.

Referenced by [6].

[6] ba=ab

Overlap of [4] aba=ba with [1] aab=ba:

ab a aab

Critical pair: abba=baab.

Reduce LHS:

[3]a(bba)
[1]⇒ (aab)a
[5]⇒ (baa)
⇒ ba

Reduce RHS:

[5](baa)b
[2]⇒ (bab)
⇒ ab

Defines rule #1.

Referenced by [7], [8].

[7] abb=ab

Overlap of [4] aba=ba with [2] bab=ab:

a ba bab

Critical pair: aab=bab.

Reduce LHS:

[1](aab)
[6]⇒ (ba)
⇒ ab

Reduce RHS:

[6](ba)b
⇒ abb

Flip LHS and RHS.

Defines rule #3.

[8] aab=ab

Simplify [1] aab=ba.

Reduce RHS:

[6](ba)
⇒ ab

Defines rule #2.