| Back: | ⟨a, b | aba=ab, bbba=a⟩ |
|---|
Completion settings:
Axiom: aba=ab.
Defines rule #4.
Axiom: bbba=a.
Defines rule #2.
Overlap of [1] aba=ab with [1] aba=ab:
Critical pair: abab=abba.
Reduce LHS:
| [1] | (aba)b |
| ⇒ abb |
Flip LHS and RHS.
Defines rule #5.
Overlap of [1] aba=ab with [3] abba=abb:
Critical pair: ababb=abbba.
Reduce LHS:
| [1] | (aba)bb |
| ⇒ abbb |
Reduce RHS:
| [2] | a(bbba) |
| ⇒ aa |
Flip LHS and RHS.
Defines rule #3.
Overlap of [3] abba=abb with [3] abba=abb:
Critical pair: abbabb=abbbba.
Reduce LHS:
| [3] | (abba)bb |
| ⇒ abbbb |
Reduce RHS:
| [2] | ab(bbba) |
| [1] | ⇒ (aba) |
| ⇒ ab |
Defines rule #1.