| Back: | ⟨a, b | aa=a, bababbb=a⟩ |
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Completion settings:
Axiom: aa=a.
Defines rule #3.
Referenced by [3], [4], [5], [7], [8], [10], [11], [12], [13].
Axiom: bababbb=a.
Referenced by [3], [4], [6], [7], [10], [11], [12], [13], [14].
Overlap of [2] bababbb=a with [2] bababbb=a:
Critical pair: bababba=aababbb.
Reduce RHS:
| [1] | (aa)babbb |
| ⇒ ababbb |
Referenced by [4], [5], [6], [9], [11], [12], [13].
Overlap of [2] bababbb=a with [3] bababba=ababbb:
Critical pair: bababbababbb=aababba.
Reduce LHS:
| [3] | (bababba)babbb |
| ⇒ ababbbbabbb |
Reduce RHS:
| [1] | (aa)babba |
| ⇒ ababba |
Referenced by [6].
Overlap of [3] bababba=ababbb with [1] aa=a:
Critical pair: bababba=ababbba.
Reduce LHS:
| [3] | (bababba) |
| ⇒ ababbb |
Flip LHS and RHS.
Referenced by [15].
Overlap of [3] bababba=ababbb with [2] bababbb=a:
Critical pair: bababa=ababbbbabbb.
Reduce RHS:
| [4] | (ababbbbabbb) |
| ⇒ ababba |
Overlap of [6] bababa=ababba with [2] bababbb=a:
Critical pair: baa=ababbabbb.
Reduce LHS:
| [1] | b(aa) |
| ⇒ ba |
Flip LHS and RHS.
Referenced by [8], [9], [10], [11], [12], [14].
Overlap of [1] aa=a with [7] ababbabbb=ba:
Critical pair: aba=ababbabbb.
Reduce RHS:
| [7] | (ababbabbb) |
| ⇒ ba |
Referenced by [9], [10], [11], [12], [13], [14], [15].
Overlap of [3] bababba=ababbb with [7] ababbabbb=ba:
Critical pair: bba=ababbbbbb.
Reduce RHS:
| [8] | (aba)bbbbbb |
| ⇒ babbbbbb |
Referenced by [10], [11], [12], [13], [14].
Overlap of [7] ababbabbb=ba with [2] bababbb=a:
Critical pair: ababbabba=baababbb.
Reduce LHS:
| [8] | (aba)bbabba |
| [9] | ⇒ ba(bba)bba |
| [2] | ⇒ (bababbb)bbbbba |
| [9] | ⇒ abbb(bba) |
| [9] | ⇒ abb(bba)bbbbbb |
| [9] | ⇒ ab(bba)bbbbbbbbbbbb |
| [9] | ⇒ a(bba)bbbbbbbbbbbbbbbbbb |
| [8] | ⇒ (aba)bbbbbbbbbbbbbbbbbbbbbbbb |
| ⇒ babbbbbbbbbbbbbbbbbbbbbbbb |
Reduce RHS:
| [1] | b(aa)babbb |
| [2] | ⇒ (bababbb) |
| ⇒ a |
Referenced by [16].
Overlap of [7] ababbabbb=ba with [3] bababba=ababbb:
Critical pair: ababbabbababbb=baababba.
Reduce LHS:
| [8] | (aba)bbabbababbb |
| [2] | ⇒ babbab(bababbb) |
| [8] | ⇒ babb(aba) |
| [9] | ⇒ bab(bba) |
| [9] | ⇒ ba(bba)bbbbbb |
| [2] | ⇒ (bababbb)bbbbbbbbb |
| ⇒ abbbbbbbbb |
Reduce RHS:
| [1] | b(aa)babba |
| [3] | ⇒ (bababba) |
| [8] | ⇒ (aba)bbb |
| ⇒ babbb |
Flip LHS and RHS.
Overlap of [7] ababbabbb=ba with [6] bababa=ababba:
Critical pair: ababbabbababba=baababa.
Reduce LHS:
| [8] | (aba)bbabbababba |
| [3] | ⇒ babbab(bababba) |
| [6] | ⇒ bab(bababa)bbb |
| [6] | ⇒ (bababa)bbabbb |
| [8] | ⇒ (aba)bbabbabbb |
| [9] | ⇒ ba(bba)bbabbb |
| [2] | ⇒ (bababbb)bbbbbabbb |
| [9] | ⇒ abbb(bba)bbb |
| [9] | ⇒ abb(bba)bbbbbbbbb |
| [9] | ⇒ ab(bba)bbbbbbbbbbbbbbb |
| [9] | ⇒ a(bba)bbbbbbbbbbbbbbbbbbbbb |
| [8] | ⇒ (aba)bbbbbbbbbbbbbbbbbbbbbbbbbbb |
| [11] | ⇒ (babbb)bbbbbbbbbbbbbbbbbbbbbbbb |
| ⇒ abbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb |
Reduce RHS:
| [1] | b(aa)baba |
| [6] | ⇒ (bababa) |
| [8] | ⇒ (aba)bba |
| [9] | ⇒ ba(bba) |
| [2] | ⇒ (bababbb)bbb |
| ⇒ abbb |
Referenced by [13].
Overlap of [3] bababba=ababbb with [8] aba=ba:
Critical pair: bababbba=ababbbba.
Reduce LHS:
| [2] | (bababbb)a |
| [1] | ⇒ (aa) |
| ⇒ a |
Reduce RHS:
| [8] | (aba)bbbba |
| [11] | ⇒ (babbb)ba |
| [9] | ⇒ abbbbbbbb(bba) |
| [9] | ⇒ abbbbbbb(bba)bbbbbb |
| [9] | ⇒ abbbbbb(bba)bbbbbbbbbbbb |
| [9] | ⇒ abbbbb(bba)bbbbbbbbbbbbbbbbbb |
| [9] | ⇒ abbbb(bba)bbbbbbbbbbbbbbbbbbbbbbbb |
| [9] | ⇒ abbb(bba)bbbbbbbbbbbbbbbbbbbbbbbbbbbbbb |
| [12] | ⇒ abbbb(abbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb)bbb |
| [9] | ⇒ abb(bba)bbbbbb |
| [9] | ⇒ ab(bba)bbbbbbbbbbbb |
| [9] | ⇒ a(bba)bbbbbbbbbbbbbbbbbb |
| [8] | ⇒ (aba)bbbbbbbbbbbbbbbbbbbbbbbb |
| [11] | ⇒ (babbb)bbbbbbbbbbbbbbbbbbbbb |
| ⇒ abbbbbbbbbbbbbbbbbbbbbbbbbbbbbb |
Flip LHS and RHS.
Referenced by [15].
Overlap of [7] ababbabbb=ba with [8] aba=ba:
Critical pair: babbabbb=ba.
Reduce LHS:
| [9] | ba(bba)bbb |
| [2] | ⇒ (bababbb)bbbbbb |
| ⇒ abbbbbb |
Flip LHS and RHS.
Defines rule #2.
Simplify [5] ababbba=ababbb.
Reduce LHS:
| [8] | (aba)bbba |
| [14] | ⇒ (ba)bbba |
| [14] | ⇒ abbbbbbbb(ba) |
| [14] | ⇒ abbbbbbb(ba)bbbbbb |
| [14] | ⇒ abbbbbb(ba)bbbbbbbbbbbb |
| [14] | ⇒ abbbbb(ba)bbbbbbbbbbbbbbbbbb |
| [14] | ⇒ abbbb(ba)bbbbbbbbbbbbbbbbbbbbbbbb |
| [13] | ⇒ abbbb(abbbbbbbbbbbbbbbbbbbbbbbbbbbbbb) |
| [14] | ⇒ abbb(ba) |
| [14] | ⇒ abb(ba)bbbbbb |
| [14] | ⇒ ab(ba)bbbbbbbbbbbb |
| [8] | ⇒ (aba)bbbbbbbbbbbbbbbbbb |
| [14] | ⇒ (ba)bbbbbbbbbbbbbbbbbb |
| ⇒ abbbbbbbbbbbbbbbbbbbbbbbb |
Reduce RHS:
| [8] | (aba)bbb |
| [14] | ⇒ (ba)bbb |
| ⇒ abbbbbbbbb |
Referenced by [16].
Simplify [10] babbbbbbbbbbbbbbbbbbbbbbbb=a.
Reduce LHS:
| [15] | b(abbbbbbbbbbbbbbbbbbbbbbbb) |
| [14] | ⇒ (ba)bbbbbbbbb |
| ⇒ abbbbbbbbbbbbbbb |
Defines rule #1.