| Back: | ⟨a, b | aba=b, baab=bbb⟩ |
|---|
Completion settings:
Axiom: aba=b.
Defines rule #1.
Referenced by [3], [4], [5], [6], [8].
Axiom: baab=bbb.
Referenced by [4], [5], [6], [9], [10].
Overlap of [1] aba=b with [1] aba=b:
Critical pair: abb=bba.
Flip LHS and RHS.
Defines rule #3.
Overlap of [1] aba=b with [2] baab=bbb:
Critical pair: abbb=bab.
Overlap of [2] baab=bbb with [1] aba=b:
Critical pair: bab=bbba.
Reduce RHS:
| [3] | b(bba) |
| ⇒ babb |
Flip LHS and RHS.
Referenced by [7].
Overlap of [3] bba=abb with [2] baab=bbb:
Critical pair: bbbb=abbab.
Reduce RHS:
| [3] | a(bba)b |
| [4] | ⇒ a(abbb) |
| [1] | ⇒ (aba)b |
| ⇒ bb |
Overlap of [6] bbbb=bb with [3] bba=abb:
Critical pair: bbabb=bba.
Reduce LHS:
| [3] | (bba)bb |
| [4] | ⇒ (abbb)b |
| [5] | ⇒ (babb) |
| ⇒ bab |
Reduce RHS:
| [3] | (bba) |
| ⇒ abb |
Defines rule #2.
Referenced by [8].
Overlap of [1] aba=b with [7] bab=abb:
Critical pair: aabb=bb.
Defines rule #5.
Referenced by [9].
Overlap of [2] baab=bbb with [8] aabb=bb:
Critical pair: bbb=bbbb.
Reduce RHS:
| [6] | (bbbb) |
| ⇒ bb |
Defines rule #4.
Referenced by [10].
Simplify [2] baab=bbb.
Reduce RHS:
| [9] | (bbb) |
| ⇒ bb |
Defines rule #6.