Certificate for #20135 ⟨a, b | aab=b, baba=bbb⟩

Completion settings:

[1] aab=b

Axiom: aab=b.

Defines rule #1.

Referenced by [4], [5], [6], [7].

[2] bbb=baba

Axiom: baba=bbb.

Flip LHS and RHS.

Defines rule #2.

Referenced by [3], [4], [6], [7].

[3] babab=bbaba

Overlap of [2] bbb=baba with [2] bbb=baba:

b bb bbb

Critical pair: bbaba=babab.

Flip LHS and RHS.

Defines rule #5.

Referenced by [4], [5], [6], [7].

[4] babbab=bbabba

Overlap of [2] bbb=baba with [3] babab=bbaba:

bb b babab

Critical pair: bbbbaba=babaabab.

Reduce LHS:

[2](bbb)baba
[3]⇒ (babab)aba
[1]⇒ bbab(aab)a
⇒ bbabba

Reduce RHS:

[1]bab(aab)ab
⇒ babbab

Flip LHS and RHS.

Defines rule #7.

Referenced by [5], [7].

[5] bbabbaa=bbabb

Overlap of [3] babab=bbaba with [3] babab=bbaba:

ba bab babab

Critical pair: babbaba=bbabaab.

Reduce LHS:

[4](babbab)a
⇒ bbabbaa

Reduce RHS:

[1]bbab(aab)
⇒ bbabb

Defines rule #6.

Referenced by [6].

[6] bbabaaaa=bbabaa

Overlap of [2] bbb=baba with [5] bbabbaa=bbabb:

b bb bbabbaa

Critical pair: bbbabb=babaabbaa.

Reduce LHS:

[2](bbb)abb
[1]⇒ bab(aab)b
[2]⇒ ba(bbb)
[3]⇒ (babab)a
⇒ bbabaa

Reduce RHS:

[1]bab(aab)baa
[2]⇒ ba(bbb)aa
[3]⇒ (babab)aaa
⇒ bbabaaaa

Flip LHS and RHS.

Defines rule #3.

[7] babbaaa=babba

Overlap of [2] bbb=baba with [4] babbab=bbabba:

bb b babbab

Critical pair: bbbbabba=babaabbab.

Reduce LHS:

[2](bbb)babba
[3]⇒ (babab)abba
[1]⇒ bbab(aab)ba
[2]⇒ bba(bbb)a
[3]⇒ b(babab)aa
[2]⇒ (bbb)abaaa
[1]⇒ bab(aab)aaa
⇒ babbaaa

Reduce RHS:

[1]bab(aab)bab
[2]⇒ ba(bbb)ab
[3]⇒ (babab)aab
[1]⇒ bbaba(aab)
[3]⇒ b(babab)
[2]⇒ (bbb)aba
[1]⇒ bab(aab)a
⇒ babba

Defines rule #4.