| Back: | ⟨a, b | aba=a, babab=bb⟩ |
|---|
Completion settings:
Axiom: aba=a.
Defines rule #1.
Axiom: babab=bb.
Reduce LHS:
| [1] | b(aba)b |
| ⇒ bab |
Defines rule #3.
Overlap of [1] aba=a with [2] bab=bb:
Critical pair: abb=ab.
Defines rule #2.
Referenced by [5].
Overlap of [2] bab=bb with [1] aba=a:
Critical pair: ba=bba.
Flip LHS and RHS.
Defines rule #4.
Overlap of [2] bab=bb with [3] abb=ab:
Critical pair: bab=bbb.
Reduce LHS:
| [2] | (bab) |
| ⇒ bb |
Flip LHS and RHS.
Defines rule #5.