| Back: | ⟨a, b | aab=b, babaa=ba⟩ |
|---|
Completion settings:
Axiom: aab=b.
Defines rule #1.
Axiom: babaa=ba.
Referenced by [3], [4], [5], [8], [10].
Overlap of [2] babaa=ba with [1] aab=b:
Critical pair: babb=bab.
Defines rule #6.
Overlap of [2] babaa=ba with [1] aab=b:
Critical pair: babab=baab.
Reduce RHS:
| [1] | b(aab) |
| ⇒ bb |
Overlap of [3] babb=bab with [2] babaa=ba:
Critical pair: babba=bababaa.
Reduce LHS:
| [3] | (babb)a |
| ⇒ baba |
Reduce RHS:
| [4] | (babab)aa |
| ⇒ bbaa |
Flip LHS and RHS.
Referenced by [9].
Overlap of [3] babb=bab with [3] babb=bab:
Critical pair: babbab=bababb.
Reduce LHS:
| [3] | (babb)ab |
| [4] | ⇒ (babab) |
| ⇒ bb |
Reduce RHS:
| [4] | (babab)b |
| ⇒ bbb |
Flip LHS and RHS.
Defines rule #3.
Overlap of [3] babb=bab with [4] babab=bb:
Critical pair: babbb=bababab.
Reduce LHS:
| [3] | (babb)b |
| [3] | ⇒ (babb) |
| ⇒ bab |
Reduce RHS:
| [4] | (babab)ab |
| ⇒ bbab |
Flip LHS and RHS.
Referenced by [8].
Overlap of [7] bbab=bab with [2] babaa=ba:
Critical pair: bba=babaa.
Reduce RHS:
| [2] | (babaa) |
| ⇒ ba |
Defines rule #2.
Referenced by [9].
Simplify [5] bbaa=baba.
Reduce LHS:
| [8] | (bba)a |
| ⇒ baa |
Flip LHS and RHS.
Defines rule #5.
Referenced by [10].
Overlap of [2] babaa=ba with [9] baba=baa:
Critical pair: baaa=ba.
Defines rule #4.