| Back: | ⟨a, b | aaa=a, aabbb=ba⟩ |
|---|
Completion settings:
Axiom: aaa=a.
Defines rule #7.
Referenced by [3], [4], [9], [10].
Axiom: aabbb=ba.
Defines rule #4.
Referenced by [3], [5], [6], [7], [8], [9].
Overlap of [1] aaa=a with [2] aabbb=ba:
Critical pair: aba=abbb.
Defines rule #5.
Referenced by [4], [5], [8], [11], [12], [13], [15].
Overlap of [3] aba=abbb with [1] aaa=a:
Critical pair: aba=abbbaa.
Reduce LHS:
| [3] | (aba) |
| ⇒ abbb |
Flip LHS and RHS.
Referenced by [13].
Overlap of [3] aba=abbb with [2] aabbb=ba:
Critical pair: abba=abbbabbb.
Flip LHS and RHS.
Overlap of [2] aabbb=ba with [5] abbbabbb=abba:
Critical pair: aabba=baabbb.
Reduce RHS:
| [2] | b(aabbb) |
| ⇒ bba |
Overlap of [6] aabba=bba with [2] aabbb=ba:
Critical pair: aabbba=bbaabbb.
Reduce LHS:
| [2] | (aabbb)a |
| ⇒ baa |
Reduce RHS:
| [2] | bb(aabbb) |
| ⇒ bbba |
Referenced by [9], [10], [11], [13], [14].
Overlap of [6] aabba=bba with [6] aabba=bba:
Critical pair: aabbbba=bbaabba.
Reduce LHS:
| [2] | (aabbb)ba |
| [3] | ⇒ b(aba) |
| ⇒ babbb |
Reduce RHS:
| [6] | bb(aabba) |
| ⇒ bbbba |
Flip LHS and RHS.
Overlap of [2] aabbb=ba with [7] baa=bbba:
Critical pair: aabbbbba=baaa.
Reduce LHS:
| [2] | (aabbb)bba |
| ⇒ babba |
Reduce RHS:
| [1] | b(aaa) |
| ⇒ ba |
Overlap of [7] baa=bbba with [1] aaa=a:
Critical pair: ba=bbbaa.
Reduce RHS:
| [7] | bb(baa) |
| [8] | ⇒ b(bbbba) |
| ⇒ bbabbb |
Flip LHS and RHS.
Referenced by [12].
Overlap of [9] babba=ba with [7] baa=bbba:
Critical pair: babbbba=baa.
Reduce LHS:
| [8] | ba(bbbba) |
| [3] | ⇒ b(aba)bbb |
| ⇒ babbbbbb |
Reduce RHS:
| [7] | (baa) |
| ⇒ bbba |
Flip LHS and RHS.
Referenced by [12], [13], [14].
Overlap of [11] bbba=babbbbbb with [3] aba=abbb:
Critical pair: bbbabbb=babbbbbbba.
Reduce LHS:
| [10] | b(bbabbb) |
| ⇒ bba |
Reduce RHS:
| [11] | babbbb(bbba) |
| [10] | ⇒ babbb(bbabbb)bbb |
| [10] | ⇒ babb(bbabbb) |
| [11] | ⇒ ba(bbba) |
| [3] | ⇒ b(aba)bbbbbb |
| ⇒ babbbbbbbbb |
Defines rule #3.
Overlap of [4] abbbaa=abbb with [7] baa=bbba:
Critical pair: abbbbba=abbb.
Reduce LHS:
| [11] | abb(bbba) |
| [5] | ⇒ (abbbabbb)bbb |
| [12] | ⇒ a(bba)bbb |
| [3] | ⇒ (aba)bbbbbbbbbbbb |
| ⇒ abbbbbbbbbbbbbbb |
Defines rule #1.
Simplify [7] baa=bbba.
Reduce RHS:
| [11] | (bbba) |
| ⇒ babbbbbb |
Defines rule #6.
Overlap of [9] babba=ba with [12] bba=babbbbbbbbb:
Critical pair: bababbbbbbbbb=ba.
Reduce LHS:
| [3] | b(aba)bbbbbbbbb |
| ⇒ babbbbbbbbbbbb |
Defines rule #2.