Certificate for #19212 ⟨a, b | aba=b, baaaab=a⟩

Completion settings:

[1] aba=b

Axiom: aba=b.

Referenced by [3], [4], [5], [6], [7], [8].

[2] baaaab=a

Axiom: baaaab=a.

Referenced by [4], [5], [9], [11], [13].

[3] abb=bba

Overlap of [1] aba=b with [1] aba=b:

ab a aba

Critical pair: abb=bba.

Referenced by [5], [10].

[4] baaab=aa

Overlap of [1] aba=b with [2] baaaab=a:

a ba baaaab

Critical pair: aa=baaab.

Flip LHS and RHS.

Referenced by [6], [13].

[5] bbaaaaab=b

Overlap of [3] abb=bba with [2] baaaab=a:

ab b baaaab

Critical pair: aba=bbaaaaab.

Reduce LHS:

[1](aba)
⇒ b

Flip LHS and RHS.

Referenced by [12].

[6] baab=aaa

Overlap of [1] aba=b with [4] baaab=aa:

a ba baaab

Critical pair: aaa=baab.

Flip LHS and RHS.

Referenced by [7].

[7] bab=aaaa

Overlap of [1] aba=b with [6] baab=aaa:

a ba baab

Critical pair: aaaa=bab.

Flip LHS and RHS.

Referenced by [8], [10].

[8] bb=aaaaa

Overlap of [1] aba=b with [7] bab=aaaa:

a ba bab

Critical pair: aaaaa=bb.

Flip LHS and RHS.

Defines rule #4.

Referenced by [9], [10], [11], [12].

[9] ab=baaaaaaaaa

Overlap of [2] baaaab=a with [8] bb=aaaaa:

baaaa b bb

Critical pair: baaaaaaaaa=ab.

Flip LHS and RHS.

Defines rule #3.

Referenced by [10], [11], [12], [13].

[10] baaaaaaaaaaaaaa=baaaa

Overlap of [3] abb=bba with [8] bb=aaaaa:

ab b bb

Critical pair: abaaaaa=bbab.

Reduce LHS:

[9](ab)aaaaa
⇒ baaaaaaaaaaaaaa

Reduce RHS:

[7]b(bab)
⇒ baaaa

Referenced by [11].

[11] baaaaaaaaaaa=ba

Overlap of [8] bb=aaaaa with [2] baaaab=a:

b b baaaab

Critical pair: ba=aaaaaaaaab.

Reduce RHS:

[9]aaaaaaaa(ab)
[9]⇒ aaaaaaa(ab)aaaaaaaaa
[10]⇒ aaaaaaa(baaaaaaaaaaaaaa)aaaa
[9]⇒ aaaaaa(ab)aaaaaaaa
[10]⇒ aaaaaa(baaaaaaaaaaaaaa)aaa
[9]⇒ aaaaa(ab)aaaaaaa
[10]⇒ aaaaa(baaaaaaaaaaaaaa)aa
[9]⇒ aaaa(ab)aaaaaa
[10]⇒ aaaa(baaaaaaaaaaaaaa)a
[9]⇒ aaa(ab)aaaaa
[10]⇒ aaa(baaaaaaaaaaaaaa)
[9]⇒ aa(ab)aaaa
[9]⇒ a(ab)aaaaaaaaaaaaa
[10]⇒ a(baaaaaaaaaaaaaa)aaaaaaaa
[9]⇒ (ab)aaaaaaaaaaaa
[10]⇒ (baaaaaaaaaaaaaa)aaaaaaa
⇒ baaaaaaaaaaa

Flip LHS and RHS.

Referenced by [12].

[12] baaaaaaaaaa=b

Simplify [5] bbaaaaab=b.

Reduce LHS:

[8](bb)aaaaab
[9]⇒ aaaaaaaaa(ab)
[9]⇒ aaaaaaaa(ab)aaaaaaaaa
[11]⇒ aaaaaaaa(baaaaaaaaaaa)aaaaaaa
[9]⇒ aaaaaaa(ab)aaaaaaaa
[11]⇒ aaaaaaa(baaaaaaaaaaa)aaaaaa
[9]⇒ aaaaaa(ab)aaaaaaa
[11]⇒ aaaaaa(baaaaaaaaaaa)aaaaa
[9]⇒ aaaaa(ab)aaaaaa
[11]⇒ aaaaa(baaaaaaaaaaa)aaaa
[9]⇒ aaaa(ab)aaaaa
[11]⇒ aaaa(baaaaaaaaaaa)aaa
[9]⇒ aaa(ab)aaaa
[11]⇒ aaa(baaaaaaaaaaa)aa
[9]⇒ aa(ab)aaa
[11]⇒ aa(baaaaaaaaaaa)a
[9]⇒ a(ab)aa
[11]⇒ a(baaaaaaaaaaa)
[9]⇒ (ab)a
⇒ baaaaaaaaaa

Defines rule #2.

[13] aaaaaaaaaaa=a

Overlap of [2] baaaab=a with [9] ab=baaaaaaaaa:

baaa ab ab

Critical pair: baaabaaaaaaaaa=a.

Reduce LHS:

[4](baaab)aaaaaaaaa
⇒ aaaaaaaaaaa

Defines rule #1.