| Back: | ⟨a, b | aba=ab, bba=a⟩ |
|---|
Completion settings:
Axiom: aba=ab.
Defines rule #4.
Axiom: bba=a.
Defines rule #2.
Referenced by [3].
Overlap of [1] aba=ab with [1] aba=ab:
Critical pair: abab=abba.
Reduce LHS:
| [1] | (aba)b |
| ⇒ abb |
Reduce RHS:
| [2] | a(bba) |
| ⇒ aa |
Flip LHS and RHS.
Defines rule #3.
Referenced by [4].
Overlap of [1] aba=ab with [3] aa=abb:
Critical pair: ababb=aba.
Reduce LHS:
| [1] | (aba)bb |
| ⇒ abbb |
Reduce RHS:
| [1] | (aba) |
| ⇒ ab |
Defines rule #1.