| Back: | ⟨a, b | aba=bb, baa=aba⟩ |
|---|
Completion settings:
Axiom: aba=bb.
Defines rule #3.
Axiom: baa=aba.
Reduce RHS:
| [1] | (aba) |
| ⇒ bb |
Defines rule #1.
Overlap of [1] aba=bb with [2] baa=bb:
Critical pair: abb=bba.
Defines rule #2.
Referenced by [4].
Overlap of [3] abb=bba with [2] baa=bb:
Critical pair: abbb=bbaaa.
Reduce LHS:
| [3] | (abb)b |
| ⇒ bbab |
Reduce RHS:
| [2] | b(baa)a |
| ⇒ bbba |
Defines rule #4.