| Back: | ⟨a, b | aab=bb, abaa=ba⟩ |
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Axiom: aab=bb.
Defines rule #4.
Referenced by [3], [4], [5], [6], [7], [8], [9], [11].
Axiom: abaa=ba.
Referenced by [3], [4], [5], [11].
Overlap of [1] aab=bb with [2] abaa=ba:
Critical pair: aba=bbaa.
Flip LHS and RHS.
Referenced by [8], [9], [10], [11], [12].
Overlap of [2] abaa=ba with [1] aab=bb:
Critical pair: abbb=bab.
Flip LHS and RHS.
Defines rule #2.
Referenced by [5], [6], [7], [8], [9], [10].
Overlap of [2] abaa=ba with [1] aab=bb:
Critical pair: ababb=baab.
Reduce LHS:
| [4] | a(bab)b |
| [1] | ⇒ (aab)bbb |
| ⇒ bbbbb |
Reduce RHS:
| [1] | b(aab) |
| ⇒ bbb |
Overlap of [1] aab=bb with [4] bab=abbb:
Critical pair: aaabbb=bbab.
Reduce LHS:
| [1] | a(aab)bb |
| ⇒ abbbb |
Reduce RHS:
| [4] | b(bab) |
| [4] | ⇒ (bab)bb |
| [5] | ⇒ a(bbbbb) |
| ⇒ abbb |
Overlap of [4] bab=abbb with [4] bab=abbb:
Critical pair: baabbb=abbbab.
Reduce LHS:
| [1] | b(aab)bb |
| [5] | ⇒ (bbbbb) |
| ⇒ bbb |
Reduce RHS:
| [4] | abb(bab) |
| [4] | ⇒ ab(bab)bb |
| [6] | ⇒ ab(abbbb)b |
| [6] | ⇒ ab(abbbb) |
| [4] | ⇒ a(bab)bb |
| [1] | ⇒ (aab)bbbb |
| [5] | ⇒ (bbbbb)b |
| ⇒ bbbb |
Flip LHS and RHS.
Defines rule #1.
Referenced by [10].
Overlap of [1] aab=bb with [3] bbaa=aba:
Critical pair: aaaba=bbbaa.
Reduce LHS:
| [1] | a(aab)a |
| ⇒ abba |
Reduce RHS:
| [3] | b(bbaa) |
| [4] | ⇒ (bab)a |
| ⇒ abbba |
Flip LHS and RHS.
Overlap of [4] bab=abbb with [3] bbaa=aba:
Critical pair: baaba=abbbbaa.
Reduce LHS:
| [1] | b(aab)a |
| ⇒ bbba |
Reduce RHS:
| [6] | (abbbb)aa |
| [8] | ⇒ (abbba)a |
| [3] | ⇒ a(bbaa) |
| [1] | ⇒ (aab)a |
| ⇒ bba |
Referenced by [10].
Overlap of [7] bbbb=bbb with [3] bbaa=aba:
Critical pair: bbaba=bbbaa.
Reduce LHS:
| [4] | b(bab)a |
| [8] | ⇒ b(abbba) |
| [4] | ⇒ (bab)ba |
| [6] | ⇒ (abbbb)a |
| [8] | ⇒ (abbba) |
| ⇒ abba |
Reduce RHS:
| [9] | (bbba)a |
| [3] | ⇒ (bbaa) |
| ⇒ aba |
Referenced by [11].
Overlap of [10] abba=aba with [3] bbaa=aba:
Critical pair: aaba=abaa.
Reduce LHS:
| [1] | (aab)a |
| ⇒ bba |
Reduce RHS:
| [2] | (abaa) |
| ⇒ ba |
Defines rule #3.
Referenced by [12].
Overlap of [3] bbaa=aba with [11] bba=ba:
Critical pair: baa=aba.
Defines rule #5.