Certificate for #16291 ⟨a, b | aab=bb, abaa=ba

Completion settings:

[1] aab=bb

Axiom: aab=bb.

Defines rule #4.

Referenced by [3], [4], [5], [6], [7], [8], [9], [11].

[2] abaa=ba

Axiom: abaa=ba.

Referenced by [3], [4], [5], [11].

[3] bbaa=aba

Overlap of [1] aab=bb with [2] abaa=ba:

a ab abaa

Critical pair: aba=bbaa.

Flip LHS and RHS.

Referenced by [8], [9], [10], [11], [12].

[4] bab=abbb

Overlap of [2] abaa=ba with [1] aab=bb:

ab aa aab

Critical pair: abbb=bab.

Flip LHS and RHS.

Defines rule #2.

Referenced by [5], [6], [7], [8], [9], [10].

[5] bbbbb=bbb

Overlap of [2] abaa=ba with [1] aab=bb:

aba a aab

Critical pair: ababb=baab.

Reduce LHS:

[4]a(bab)b
[1](aab)bbb
bbbbb

Reduce RHS:

[1]b(aab)
bbb

Referenced by [6], [7].

[6] abbbb=abbb

Overlap of [1] aab=bb with [4] bab=abbb:

aa b bab

Critical pair: aaabbb=bbab.

Reduce LHS:

[1]a(aab)bb
abbbb

Reduce RHS:

[4]b(bab)
[4](bab)bb
[5]a(bbbbb)
abbb

Referenced by [7], [9], [10].

[7] bbbb=bbb

Overlap of [4] bab=abbb with [4] bab=abbb:

ba b bab

Critical pair: baabbb=abbbab.

Reduce LHS:

[1]b(aab)bb
[5](bbbbb)
bbb

Reduce RHS:

[4]abb(bab)
[4]ab(bab)bb
[6]ab(abbbb)b
[6]ab(abbbb)
[4]a(bab)bb
[1](aab)bbbb
[5](bbbbb)b
bbbb

Flip LHS and RHS.

Defines rule #1.

Referenced by [10].

[8] abbba=abba

Overlap of [1] aab=bb with [3] bbaa=aba:

aa b bbaa

Critical pair: aaaba=bbbaa.

Reduce LHS:

[1]a(aab)a
abba

Reduce RHS:

[3]b(bbaa)
[4](bab)a
abbba

Flip LHS and RHS.

Referenced by [9], [10].

[9] bbba=bba

Overlap of [4] bab=abbb with [3] bbaa=aba:

ba b bbaa

Critical pair: baaba=abbbbaa.

Reduce LHS:

[1]b(aab)a
bbba

Reduce RHS:

[6](abbbb)aa
[8](abbba)a
[3]a(bbaa)
[1](aab)a
bba

Referenced by [10].

[10] abba=aba

Overlap of [7] bbbb=bbb with [3] bbaa=aba:

bb bb bbaa

Critical pair: bbaba=bbbaa.

Reduce LHS:

[4]b(bab)a
[8]b(abbba)
[4](bab)ba
[6](abbbb)a
[8](abbba)
abba

Reduce RHS:

[9](bbba)a
[3](bbaa)
aba

Referenced by [11].

[11] bba=ba

Overlap of [10] abba=aba with [3] bbaa=aba:

a bba bbaa

Critical pair: aaba=abaa.

Reduce LHS:

[1](aab)a
bba

Reduce RHS:

[2](abaa)
ba

Defines rule #3.

Referenced by [12].

[12] baa=aba

Overlap of [3] bbaa=aba with [11] bba=ba:

bbaa bba

Critical pair: baa=aba.

Defines rule #5.