| Back: | ⟨a, b | aab=bb, aaba=ba⟩ |
|---|
Completion settings:
Axiom: aab=bb.
Defines rule #1.
Axiom: aaba=ba.
Reduce LHS:
| [1] | (aab)a |
| ⇒ bba |
Defines rule #2.
Referenced by [3].
Overlap of [2] bba=ba with [1] aab=bb:
Critical pair: bbbb=baab.
Reduce RHS:
| [1] | b(aab) |
| ⇒ bbb |
Defines rule #3.