Certificate for #16052 ⟨a, b | aaa=bb, aaba=aa⟩

Completion settings:

[1] aaa=bb

Axiom: aaa=bb.

Defines rule #4.

Referenced by [3], [4], [5], [7].

[2] aaba=aa

Axiom: aaba=aa.

Defines rule #5.

Referenced by [4], [5].

[3] bba=abb

Overlap of [1] aaa=bb with [1] aaa=bb:

a aa aaa

Critical pair: abb=bba.

Flip LHS and RHS.

Referenced by [4], [5], [6], [8], [9].

[4] babb=bb

Overlap of [1] aaa=bb with [2] aaba=aa:

a aa aaba

Critical pair: aaa=bbba.

Reduce LHS:

[1](aaa)
⇒ bb

Reduce RHS:

[3]b(bba)
⇒ babb

Flip LHS and RHS.

Referenced by [6], [8].

[5] aabbb=abb

Overlap of [2] aaba=aa with [1] aaa=bb:

aab a aaa

Critical pair: aabbb=aaaa.

Reduce RHS:

[1](aaa)a
[3]⇒ (bba)
⇒ abb

Referenced by [7], [8].

[6] abbbb=bbb

Overlap of [3] bba=abb with [4] babb=bb:

b ba babb

Critical pair: bbb=abbbb.

Flip LHS and RHS.

Referenced by [7], [8].

[7] abb=bbbbbb

Overlap of [1] aaa=bb with [6] abbbb=bbb:

aa a abbbb

Critical pair: aabbb=bbbbbb.

Reduce LHS:

[5](aabbb)
⇒ abb

Defines rule #2.

Referenced by [8], [9].

[8] bbbbbbb=bb

Overlap of [6] abbbb=bbb with [3] bba=abb:

abb bb bba

Critical pair: abbabb=bbba.

Reduce LHS:

[3]a(bba)bb
[5]⇒ (aabbb)b
[7]⇒ (abb)b
⇒ bbbbbbb

Reduce RHS:

[3]b(bba)
[4]⇒ (babb)
⇒ bb

Defines rule #1.

[9] bba=bbbbbb

Simplify [3] bba=abb.

Reduce RHS:

[7](abb)
⇒ bbbbbb

Defines rule #3.