| Back: | ⟨a, b | aaba=a, bbaaa=a⟩ |
|---|
Completion settings:
Axiom: aaba=a.
Axiom: bbaaa=a.
Referenced by [4].
Axiom: bba=c.
Defines rule #9.
Referenced by [4], [5], [9], [13].
Overlap of [2] bbaaa=a with [3] bba=c:
Critical pair: caa=a.
Overlap of [3] bba=c with [1] aaba=a:
Critical pair: bba=caba.
Reduce LHS:
| [3] | (bba) |
| ⇒ c |
Flip LHS and RHS.
Referenced by [7].
Overlap of [4] caa=a with [1] aaba=a:
Critical pair: ca=aba.
Flip LHS and RHS.
Referenced by [7], [10], [11], [18].
Overlap of [6] aba=ca with [6] aba=ca:
Critical pair: abca=caba.
Reduce RHS:
| [5] | (caba) |
| ⇒ c |
Referenced by [8], [9], [10], [11], [12], [14].
Overlap of [1] aaba=a with [7] abca=c:
Critical pair: aabc=abca.
Reduce RHS:
| [7] | (abca) |
| ⇒ c |
Referenced by [15].
Overlap of [3] bba=c with [7] abca=c:
Critical pair: bbc=cbca.
Overlap of [6] aba=ca with [7] abca=c:
Critical pair: abc=cabca.
Reduce RHS:
| [7] | c(abca) |
| ⇒ cc |
Defines rule #5.
Referenced by [11], [12], [13], [14], [15].
Overlap of [7] abca=c with [6] aba=ca:
Critical pair: abcca=cba.
Reduce LHS:
| [10] | (abc)ca |
| ⇒ ccca |
Flip LHS and RHS.
Overlap of [7] abca=c with [7] abca=c:
Critical pair: abcc=cbca.
Reduce LHS:
| [10] | (abc)c |
| ⇒ ccc |
Flip LHS and RHS.
Referenced by [13].
Overlap of [3] bba=c with [10] abc=cc:
Critical pair: bbcc=cbc.
Reduce LHS:
| [9] | (bbc)c |
| [12] | ⇒ (cbca)c |
| ⇒ cccc |
Flip LHS and RHS.
Defines rule #3.
Overlap of [7] abca=c with [10] abc=cc:
Critical pair: cca=c.
Referenced by [16], [19], [20].
Simplify [8] aabc=c.
Reduce LHS:
| [10] | a(abc) |
| ⇒ acc |
Defines rule #1.
Referenced by [16].
Overlap of [15] acc=c with [14] cca=c:
Critical pair: ac=ca.
Flip LHS and RHS.
Defines rule #2.
Referenced by [17], [18], [19].
Overlap of [4] caa=a with [16] ca=ac:
Critical pair: aca=a.
Reduce LHS:
| [16] | a(ca) |
| ⇒ aac |
Defines rule #4.
Simplify [6] aba=ca.
Reduce RHS:
| [16] | (ca) |
| ⇒ ac |
Defines rule #8.
Simplify [9] bbc=cbca.
Reduce RHS:
| [16] | cb(ca) |
| [11] | ⇒ (cba)c |
| [14] | ⇒ c(cca)c |
| ⇒ ccc |
Defines rule #7.
Simplify [11] cba=ccca.
Reduce RHS:
| [14] | c(cca) |
| ⇒ cc |
Defines rule #6.