Certificate for #1427 ⟨a, b | abba=b, baba=1⟩

Completion settings:

[1] abba=b

Axiom: abba=b.

Referenced by [3], [4], [5], [6], [7], [8].

[2] baba=1

Axiom: baba=1.

Referenced by [4], [5], [10].

[3] bbba=abbb

Overlap of [1] abba=b with [1] abba=b:

abb a abba

Critical pair: abbb=bbba.

Flip LHS and RHS.

Referenced by [6], [10].

[4] bba=ab

Overlap of [1] abba=b with [2] baba=1:

ab ba baba

Critical pair: ab=bba.

Flip LHS and RHS.

Referenced by [5], [6], [8], [9].

[5] babb=ab

Overlap of [2] baba=1 with [1] abba=b:

bab a abba

Critical pair: babb=bba.

Reduce RHS:

[4](bba)
ab

Referenced by [7], [8].

[6] aabbb=bbb

Overlap of [4] bba=ab with [1] abba=b:

bb a abba

Critical pair: bbb=abbba.

Reduce RHS:

[3]a(bbba)
aabbb

Flip LHS and RHS.

Referenced by [10].

[7] aba=bb

Overlap of [5] babb=ab with [1] abba=b:

b abb abba

Critical pair: bb=aba.

Flip LHS and RHS.

Referenced by [8], [11].

[8] bbbb=b

Overlap of [5] babb=ab with [4] bba=ab:

bab b bba

Critical pair: babab=abba.

Reduce LHS:

[7]b(aba)b
bbbb

Reduce RHS:

[1](abba)
b

Referenced by [9].

[9] ba=abb

Overlap of [8] bbbb=b with [4] bba=ab:

bb bb bba

Critical pair: bbab=ba.

Reduce LHS:

[4](bba)b
abb

Flip LHS and RHS.

Defines rule #2.

Referenced by [10], [11].

[10] bbb=1

Overlap of [2] baba=1 with [9] ba=abb:

baba ba

Critical pair: abbba=1.

Reduce LHS:

[3]a(bbba)
[6](aabbb)
bbb

Defines rule #1.

Referenced by [12].

[11] aabb=bb

Simplify [7] aba=bb.

Reduce LHS:

[9]a(ba)
aabb

Referenced by [12].

[12] aa=1

Overlap of [11] aabb=bb with [10] bbb=1:

aa bb bbb

Critical pair: aa=bbb.

Reduce RHS:

[10](bbb)
⇒ 1

Defines rule #3.