| Back: | ⟨a, b | abb=aba, baa=ab⟩ |
|---|
Completion settings:
Axiom: abb=aba.
Referenced by [3].
Axiom: baa=ab.
Flip LHS and RHS.
Defines rule #2.
Simplify [1] abb=aba.
Reduce RHS:
| [2] | (ab)a |
| ⇒ baaa |
Referenced by [4].
Overlap of [3] abb=baaa with [2] ab=baa:
Critical pair: baab=baaa.
Reduce LHS:
| [2] | ba(ab) |
| [2] | ⇒ b(ab)aa |
| ⇒ bbaaaa |
Referenced by [5], [6], [7], [8].
Overlap of [4] bbaaaa=baaa with [2] ab=baa:
Critical pair: bbaaabaa=baaab.
Reduce LHS:
| [2] | bbaa(ab)aa |
| [2] | ⇒ bba(ab)aaaa |
| [2] | ⇒ bb(ab)aaaaaa |
| [4] | ⇒ b(bbaaaa)aaaa |
| [4] | ⇒ (bbaaaa)aaa |
| ⇒ baaaaaa |
Reduce RHS:
| [2] | baa(ab) |
| [2] | ⇒ ba(ab)aa |
| [2] | ⇒ b(ab)aaaa |
| [4] | ⇒ (bbaaaa)aa |
| ⇒ baaaaa |
Referenced by [6].
Overlap of [4] bbaaaa=baaa with [5] baaaaaa=baaaaa:
Critical pair: bbaaaaa=baaaaa.
Reduce LHS:
| [4] | (bbaaaa)a |
| ⇒ baaaa |
Flip LHS and RHS.
Referenced by [7].
Overlap of [4] bbaaaa=baaa with [6] baaaaa=baaaa:
Critical pair: bbaaaa=baaaa.
Reduce LHS:
| [4] | (bbaaaa) |
| ⇒ baaa |
Flip LHS and RHS.
Defines rule #1.
Referenced by [8].
Overlap of [4] bbaaaa=baaa with [7] baaaa=baaa:
Critical pair: bbaaa=baaa.
Defines rule #3.