| Back: | ⟨a, b | aba=aab, aabbb=1⟩ |
|---|
Completion settings:
Axiom: aba=aab.
Flip LHS and RHS.
Defines rule #1.
Axiom: aabbb=1.
Reduce LHS:
| [1] | (aab)bb |
| ⇒ ababb |
Defines rule #2.
Referenced by [3].
Overlap of [1] aab=aba with [2] ababb=1:
Critical pair: a=abaabb.
Reduce RHS:
| [1] | ab(aab)b |
| ⇒ ababab |
Flip LHS and RHS.
Defines rule #3.