| Back: | ⟨a, b | aaba=ba, bbba=a⟩ |
|---|
Completion settings:
Axiom: aaba=ba.
Defines rule #2.
Axiom: bbba=a.
Defines rule #3.
Referenced by [4].
Overlap of [1] aaba=ba with [1] aaba=ba:
Critical pair: aabba=baaba.
Reduce RHS:
| [1] | b(aaba) |
| ⇒ bba |
Defines rule #4.
Referenced by [4].
Overlap of [1] aaba=ba with [3] aabba=bba:
Critical pair: aabbba=baabba.
Reduce LHS:
| [2] | aa(bbba) |
| ⇒ aaa |
Reduce RHS:
| [3] | b(aabba) |
| [2] | ⇒ (bbba) |
| ⇒ a |
Defines rule #1.