| Back: | ⟨a, b | aaaa=ab, baab=b⟩ |
|---|
Completion settings:
Axiom: aaaa=ab.
Flip LHS and RHS.
Defines rule #3.
Axiom: baab=b.
Reduce LHS:
| [1] | ba(ab) |
| ⇒ baaaaa |
Defines rule #2.
Overlap of [1] ab=aaaa with [2] baaaaa=b:
Critical pair: ab=aaaaaaaaa.
Reduce LHS:
| [1] | (ab) |
| ⇒ aaaa |
Flip LHS and RHS.
Defines rule #1.
Overlap of [2] baaaaa=b with [1] ab=aaaa:
Critical pair: baaaaaaaa=bb.
Reduce LHS:
| [2] | (baaaaa)aaa |
| ⇒ baaa |
Flip LHS and RHS.
Defines rule #4.