Certificate for #12162 ⟨a, b | aaaa=aa, babb=a

Completion settings:

[1] aaaa=aa

Axiom: aaaa=aa.

Defines rule #1.

Referenced by [6], [11].

[2] babb=a

Axiom: babb=a.

Defines rule #7.

Referenced by [3], [4], [7], [9], [10].

[3] baba=aabb

Overlap of [2] babb=a with [2] babb=a:

bab b babb

Critical pair: baba=aabb.

Defines rule #4.

Referenced by [4], [5], [7], [9].

[4] aabbbb=baa

Overlap of [3] baba=aabb with [2] babb=a:

ba ba babb

Critical pair: baa=aabbbb.

Flip LHS and RHS.

Defines rule #10.

Referenced by [6], [8], [11].

[5] aabbba=baaabb

Overlap of [3] baba=aabb with [3] baba=aabb:

ba ba baba

Critical pair: baaabb=aabbba.

Flip LHS and RHS.

Referenced by [11], [13].

[6] aabaa=baa

Overlap of [1] aaaa=aa with [4] aabbbb=baa:

aa aa aabbbb

Critical pair: aabaa=aabbbb.

Reduce RHS:

[4](aabbbb)
baa

Defines rule #2.

Referenced by [7], [8], [12].

[7] baabba=aaa

Overlap of [3] baba=aabb with [6] aabaa=baa:

bab a aabaa

Critical pair: babbaa=aabbabaa.

Reduce LHS:

[2](babb)aa
aaa

Reduce RHS:

[3]aab(baba)a
[6](aabaa)bba
baabba

Flip LHS and RHS.

Defines rule #9.

Referenced by [9], [10], [11].

[8] aabbaa=bbaa

Overlap of [6] aabaa=baa with [4] aabbbb=baa:

aab aa aabbbb

Critical pair: aabbaa=baabbbb.

Reduce RHS:

[4]b(aabbbb)
bbaa

Referenced by [9], [11].

[9] bbaa=aaabba

Overlap of [2] babb=a with [7] baabba=aaa:

bab b baabba

Critical pair: babaaa=aaabba.

Reduce LHS:

[3](baba)aa
[8](aabbaa)
bbaa

Defines rule #6.

Referenced by [11].

[10] baaba=aaabb

Overlap of [7] baabba=aaa with [2] babb=a:

baab ba babb

Critical pair: baaba=aaabb.

Defines rule #5.

[11] abaaa=baa

Overlap of [7] baabba=aaa with [4] aabbbb=baa:

baabb a aabbbb

Critical pair: baabbbaa=aaaabbbb.

Reduce LHS:

[5]b(aabbba)a
[9](bbaa)abba
[8]a(aabbaa)bba
[7]ab(baabba)
abaaa

Reduce RHS:

[1](aaaa)bbbb
[4](aabbbb)
baa

Referenced by [12].

[12] baaa=abaa

Overlap of [6] aabaa=baa with [11] abaaa=baa:

a abaa abaaa

Critical pair: abaa=baaa.

Flip LHS and RHS.

Defines rule #3.

Referenced by [13].

[13] aabbba=abaabb

Simplify [5] aabbba=baaabb.

Reduce RHS:

[12](baaa)bb
abaabb

Defines rule #8.