Morphocompletion for #998 ⟨a, b | abbabba=ab⟩

Back:⟨a, b | abbabba=ab⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbab ⇒ abbba
2. abbbab ⇒ abbbba
3. abbbbab ⇒ abbbbba
4. abbbbaa ⇒ ab
5. abbbbbab ⇒ abbbbbba
6. abbbbbaa ⇒ abb
7. abbbbbbab ⇒ abbbbbbba
8. abbbbbbaa ⇒ abbb
9. abbbbbbbaa ⇒ abbbb
10. abbbbbbbbaa ⇒ abbbbb
11. abbbbbbbbbaa ⇒ abbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] aa, [2/3] ba
Length 3:[3/0] bbb, [3/1] abb, [3/2] baa, [3/3] bba, [3/4] bab
Length 4:[4/0] bbbb, [4/1] abbb, [4/2] bbaa, [4/3] bbab, [4/4] bbba, [4/5] abba
Length 5:[5/0] abbbb, [5/1] bbbbb, [5/2] bbbaa, [5/3] bbbba, [5/4] bbbab, [5/5] abbba
Length 6:[6/0] abbbbb, [6/1] bbbbaa, [6/2] bbbbbb, [6/3] bbbbba, [6/4] bbbbab, [6/5] abbbba
Length 7:[7/0] abbbbbb, [7/1] bbbbbaa, [7/2] bbbbbbb, [7/3] bbbbbba, [7/4] abbbbba, [7/5] bbbbbab

Considering [length 5 / frequency 0] abbbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbabba=ab⟩.