Morphocompletion for #993 ⟨a, b | abbaaab=aa

Solved by morph:3/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaaab ⇒ abbaaaa
2. abbaaab ⇒ aa
3. abbaabbaaaa ⇒ aaaaab
4. abbaaaaaaab ⇒ aabaabbaaaa
5. aaaaababaaab ⇒ aaaaabbbaaaa
6. aaaaabbbaaab ⇒ aaaaaba
7. aaaaababbbaaab ⇒ aaaaababa
8. aaaaabaabbbaaab ⇒ aaaaabaaba
9. abbaaaabaabbaaaa ⇒ aabaaaaaaab
10. aaaaabbbaabbaaaa ⇒ aaaaabaaaab
11. aaaaabababbbaaab ⇒ aaaaabababa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aab, [3/2] abb, [3/3] baa, [3/4] bba, [3/5] aba, [3/6] bbb
Length 4:[4/0] aaaa, [4/1] aaab, [4/2] bbaa, [4/3] baaa, [4/4] abba, [4/5] aaba, [4/6] aabb
Length 5:[5/0] aaaaa, [5/1] baaab, [5/2] abbaa, [5/3] bbaaa, [5/4] aaaab, [5/5] baaaa, [5/6] abbba
Length 6:[6/0] aaaaab, [6/1] bbaaab, [6/2] abbaaa, [6/3] bbaaaa, [6/4] aaaaba, [6/5] abbbaa, [6/6] abaaab
Length 7:[7/0] abbaaaa, [7/1] bbbaaab, [7/2] aaaaaba, [7/3] aaaaabb, [7/4] abbbaaa, [7/5] aaaabab, [7/6] aabbbaa

Considering [length 3 / frequency 2] abb=c.

Step 2

Rewriting system is complete. See a, b | abbaaab=aa.