Morphocompletion for #990 ⟨a, b | ababbba=ab

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbbaa ⇒ ab
2. ababbb ⇒ abbbba
3. abbbbbaa ⇒ abb
4. abbbbabaa ⇒ abab
5. abbabbb ⇒ abbbbba
6. abbbbbbaa ⇒ abbb
7. abbbbbabaa ⇒ abbab
8. abbbbabbaa ⇒ ababb
9. abbbbababaa ⇒ ababab
10. abbbabbb ⇒ abbbbbba
11. abbbbbbbaa ⇒ abbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] bbb, [3/1] abb, [3/2] baa, [3/3] bba, [3/4] bab, [3/5] aba
Length 4:[4/0] abbb, [4/1] bbbb, [4/2] bbaa, [4/3] bbba, [4/4] bbab, [4/5] abaa, [4/6] babb
Length 5:[5/0] abbbb, [5/1] bbbba, [5/2] bbbaa, [5/3] bbbbb, [5/4] babbb, [5/5] babaa, [5/6] bbbab
Length 6:[6/0] abbbbb, [6/1] abbbba, [6/2] bbbbaa, [6/3] bbabbb, [6/4] bbbbab, [6/5] bbbbba, [6/6] bbabaa
Length 7:[7/0] abbbbab, [7/1] bbbbbaa, [7/2] abbbbbb, [7/3] abbbbba, [7/4] bbbabaa, [7/5] bbbbaba, [7/6] bbbabbb

Considering [length 4 / frequency 0] abbb=c.

Step 2

Rewriting system is complete. See a, b | ababbba=ab.