Morphocompletion for #984 ⟨a, b | ababaab=ba⟩

Back:⟨a, b | ababaab=ba⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababaab ⇒ ba
2. abaabba ⇒ baaabab
3. abababa ⇒ baabaab
4. baababa ⇒ abbaaab
5. abbaaba ⇒ babaaab
6. baabaabab ⇒ abba
7. abbaaabab ⇒ baba
8. baaabbaaab ⇒ abbaa
9. abaababba ⇒ baaabbaab
10. abbaaabba ⇒ babaabaab
11. babaaababab ⇒ ababba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] baa, [3/2] bab, [3/3] aab, [3/4] bba, [3/5] abb, [3/6] aaa
Length 4:[4/0] abab, [4/1] abba, [4/2] baab, [4/3] baba, [4/4] aaba, [4/5] abaa, [4/6] baaa
Length 5:[5/0] ababa, [5/1] baaba, [5/2] abbaa, [5/3] baaab, [5/4] abaab, [5/5] aabab, [5/6] aabba
Length 6:[6/0] baabab, [6/1] abbaaa, [6/2] bbaaab, [6/3] ababab, [6/4] baaabb, [6/5] abaaba, [6/6] aababa
Length 7:[7/0] abbaaab, [7/1] baaabba, [7/2] abaabab, [7/3] baaabab, [7/4] aababba, [7/5] babaaab, [7/6] baabaab

Considering [length 5 / frequency 0] ababa=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababaab=ba⟩.