Morphocompletion for #984 ⟨a, b | ababaab=ba⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababaab ⇒ ba
2. abaabba ⇒ baaabab
3. abababa ⇒ baabaab
4. baababa ⇒ abbaaab
5. abbaaba ⇒ babaaab
6. baabaabab ⇒ abba
7. abbaaabab ⇒ baba
8. baaabbaaab ⇒ abbaa
9. abaababba ⇒ baaabbaab
10. abbaaabba ⇒ babaabaab
11. babaaababab ⇒ ababba
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab41lf:29,lp:7,ls:5,rf:18,rp:4,rs:6,lsrp:3,lprs:5
[2/1]ba38lf:28,lp:4,ls:6,rf:19,rp:7,rs:4,re:1,lsrp:5,lprs:2
[2/2]aa17lf:17,rf:14,rs:1
[2/3]bb7lf:7,rf:5,a:2
[3/0]aba24lf:17,lp:4,ls:3,rf:7,rp:1,rs:1
[3/1]baa15lf:12,lp:3,rf:10,rp:3,rs:1,lprs:1
[3/2]bab14lf:10,lp:1,ls:3,rf:5,rp:3,rs:1,lsrp:1
[3/3]aab14lf:12,ls:2,rf:9,rs:5
[3/4]bba10lf:7,ls:3,rf:5,rs:2,a:2
[3/5]abb10lf:7,lp:3,rf:5,rp:3,a:2
[3/6]aaa5lf:5,rf:4,a:4
[4/0]abab14lf:9,lp:2,ls:3,rf:2,rp:1,rs:1,lsrp:1
[4/1]abba13lf:7,lp:3,ls:3,rf:5,rp:3,rs:2,re:1,a:2
[4/2]baab10lf:7,lp:2,ls:1,rf:5,rp:1,rs:3
[4/3]baba9lf:6,lp:1,ls:2,rf:3,rp:3,rs:1,re:1
[4/4]aaba8lf:7,ls:1,rf:3,a:1
[4/5]abaa7lf:5,lp:2,rf:4
[4/6]baaa6lf:5,lp:1,rf:4,rp:2,a:4
[5/0]ababa9lf:5,lp:2,ls:2
[5/1]baaba8lf:5,lp:2,ls:1,rf:2,rp:1,a:1
[5/2]abbaa7lf:4,lp:3,rf:3,rp:2,rs:1,re:1,a:6
[5/3]baaab7lf:5,lp:1,ls:1,rf:4,rp:2,rs:2,a:4
[5/4]abaab7lf:4,lp:2,ls:1,rf:3,rs:2
[5/5]aabab7lf:5,ls:2,rf:1,rs:1,a:2
[5/6]aabba5lf:3,ls:2,rf:1,a:4
[6/0]baabab5lf:3,lp:1,ls:1,a:2
[6/1]abbaaa5lf:3,lp:2,rf:1,rp:1,a:6
[6/2]bbaaab4lf:3,ls:1,rf:1,rs:1,a:6
[6/3]ababab4lf:2,lp:1,ls:1,a:1
[6/4]baaabb3lf:2,lp:1,rf:1,rp:1,a:10
[6/5]abaaba3lf:2,lp:1,rf:1,a:2
[6/6]aababa3lf:2,ls:1,a:6
[7/0]abbaaab6lf:3,lp:2,ls:1,rf:1,rp:1,rs:1,re:1,a:6
[7/1]baaabba4lf:2,lp:1,ls:1,rf:1,rp:1,a:10
[7/2]abaabab4lf:2,lp:1,ls:1,a:2
[7/3]baaabab3lf:2,ls:1,rf:1,rp:1,rs:1,re:1,a:4
[7/4]aababba2lf:1,ls:1,a:10
[7/5]babaaab2lf:1,lp:1,rf:1,rp:1,rs:1,re:1,a:15
[7/6]baabaab2lf:1,lp:1,rf:2,rp:1,rs:2,re:1,a:1

Considering [length 5 / frequency 0] ababa=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababaab=ba⟩.