Morphocompletion for #979 ⟨a, b | abaabba=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbaaa ⇒ ab
2. ababb ⇒ abbba
3. abaabb ⇒ abbbaa
4. abbbbaaa ⇒ abb
5. abbbabaaa ⇒ abab
6. abbbaabaaa ⇒ abaab
7. abbabb ⇒ abbbba
8. abbaabb ⇒ abbbbaa
9. abbbbbaaa ⇒ abbb
10. abbbbabaaa ⇒ abbab
11. abbbabb ⇒ abbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] aa, [2/3] ba
Length 3:[3/0] abb, [3/1] aaa, [3/2] bbb, [3/3] bba, [3/4] baa, [3/5] aba, [3/6] bab
Length 4:[4/0] abbb, [4/1] baaa, [4/2] bbba, [4/3] babb, [4/4] bbaa, [4/5] abaa, [4/6] bbbb
Length 5:[5/0] abbba, [5/1] abbbb, [5/2] bbaaa, [5/3] abaaa, [5/4] bbabb, [5/5] baabb, [5/6] bbbaa
Length 6:[6/0] bbbaaa, [6/1] abbbab, [6/2] abbbba, [6/3] abbbaa, [6/4] babaaa, [6/5] abbbbb, [6/6] bbbabb
Length 7:[7/0] bbbbaaa, [7/1] bbabaaa, [7/2] abbbbab, [7/3] abbbbba, [7/4] abbbaab, [7/5] abbbaba, [7/6] abbbbaa

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | abaabba=ab.